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Nikitich [7]
3 years ago
10

Why can’t you perform single displacement reactions with group IA metals?

Chemistry
1 answer:
pishuonlain [190]3 years ago
5 0
Answer is: because alkaline metals (group IA metals) are the strongest reducing agents and most reactive metals.
Reducing agent<span> is an element  or compound that loses an </span>electron<span> to another </span>chemical species<span> in a </span>redox <span>chemical reaction and they have been oxidized.
Alkaline metals tend to lose only one electron in redox reaction.</span>
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The secondary structure of a protein is distinct from the tertiary structure of a protein mainly because the secondary structure
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Answer:

False

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What is an example of entropy from everyday life?
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A Campfire is an example, the solid wood becomes ash.
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Which of these facts best illustrates why regulation of alcohol consumption is necessary
exis [7]

So that people don’t break laws or drive under the influence.

4 0
3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0
3 years ago
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