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3 years ago

Why can’t you perform single displacement reactions with group IA metals?

1 answer:

5 0

Answer is: because alkaline metals (group IA metals) are the strongest reducing agents and most reactive metals.
Reducing agent<span> is an element or compound that loses an </span>electron<span> to another </span>chemical species<span> in a </span>redox <span>chemical reaction and they have been oxidized.
Alkaline metals tend to lose only one electron in redox reaction.</span>

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How can you increase the amount of work done when you lift a book explain

Gnoma [55]

Explanation:

In this case, while lifting the book we are working against the force of gravity.

Using the Newton's laws, we can find the force F required for lifting the book having mass (m) and acceleration due to gravity (g) that is ;

F = mg

and, the change in the position of the book that is Δx (Height)

→ Δx = Final position - Initial position

which is only the height, then the amount of work done will be calculated by :

W= mgh

Where W = Work Done

m = Mass of the Body

g = Acceleration due to Gravity

h = Height of Body being displaced

4 0

3 years ago

Which chloride is a coloured solid rtp<br>

lianna [129]

Answer:

sodium chloride

hope that helped :)

7 0

2 years ago

Read 2 more answers

1. Mg2+ and Ca2+ are in the same group on the periodic table. In terms of electronic

finlep [7]

Answer:

Se detailed explanation.

Explanation:

Hello,

In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:

- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.

- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.

- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.

- Their electron configurations are:

$Ca^{20}=1s^2,2s^2,2p^6,3s^3,3p^6,4s^2\\\\Mg^{12}=1s^2,2s^2,2p^6,3s^2$

It means that the both of them are at the $s$ region since it is the last subshell at which their electrons are.

Best regards.

8 0

3 years ago

The atomic number of fluorine is 9. How many electrons does an ion of fluorine have if it is represented by the symbol shown bel

Irina-Kira [14]

See charge on ion is -1 .

Hence it has taken 1 electron

Now first look at EC of Fluorine(F)

$\\ \bull\sf\dashrightarrow 1s^22s^22p^5$

Now one electron added .hence no of electrons is 10now

Look at the EC

$\\ \bull\sf\dashrightarrow 1s^22s^22p^6$

$\\ \bull\sf\dashrightarrow [He]$

Option C is correct.

5 0

2 years ago

Read 2 more answers

When this reaction in equilibrium is heated, a red/brown color persists. what is true about this reaction? 2no2(

dimulka [17.4K]

NO₂ is a brown gas while N₂O₄ is colorless. If heating causes a brown color to persist, then this means that heating causes the reaction to shift backwards and produce NO₂. Therefore, the reaction must be exothermic.

7 0

3 years ago