A 225 g sample of an unknown solid is heated 67C and placed into a calorimeter containing 25.6 g of water at 15.6°c. If the fina
l temperature of the solid sample and the water is 53°C, what is the specific heat of the solid?
1 answer:
Answer:
= 1.271 J/g°C
Explanation:
Heat released by the metal sample will be equivalent to the heat absorbed by water.
But heat = mass × specific heat capacity × temperature change
Thus;
Heat released by the solid;
= 225 g × c ×(67 -53) , where c is the specific heat capacity of the metal
= 3150 c joules
Heat absorbed by water;
= 25.6 g × 4.18 J/g°C × (53-15.6)
= 4002.0992 joules
Therefore;
3150 c joules = 4002.0992 joules
c =4002.0992/3150
<u> = 1.271 J/g°C</u>
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