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kobusy [5.1K]
3 years ago
10

A 225 g sample of an unknown solid is heated 67C and placed into a calorimeter containing 25.6 g of water at 15.6°c. If the fina

l temperature of the solid sample and the water is 53°C, what is the specific heat of the solid?​
Chemistry
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

= 1.271 J/g°C

Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

But heat = mass × specific heat capacity × temperature change

Thus;

Heat released by the solid;

= 225 g × c ×(67 -53) , where c is the specific heat capacity of the metal

= 3150 c joules

Heat absorbed by water;

= 25.6 g × 4.18 J/g°C × (53-15.6)

= 4002.0992  joules

Therefore;

3150 c joules = 4002.0992 joules

c =4002.0992/3150

 <u> = 1.271 J/g°C</u>

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Data Given:

Time = t = ?

Current = I = 10 A

Faradays Constant = F = 96500

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Amount Deposited = W = 17.3 g

Solution:
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                                          W  =  I t e / F

Solving for t,

                                          t  =  W F / I e
Putting values,
                                          t  =  (17.3 g × 96500) ÷ (10 A × 107.86 g)

                                          t  =  1547.79 s

                                          t  = 1.54 × 10³ s
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Cloud [144]
<span>Fe(NO3)2
The NO3 part is a poly-atomic ion with total charge -1.
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Answer:

0.01931034

Explanation:

Steps:

ρ =  m/v

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If the concentration of acetyl chloride  is increased ten times the rate of reaction is increased ten times.

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In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the  methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

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