I believe it is type, from what I know.
The numerical value of Kc is 1.129 x10^4
<u><em> Explanation</em></u>
C3H6O +4O2→ 3 CO2 + 3H2O
KC is the ratio of concentration of the product over the reactant.
Each concentration of product and reactant are raised to the power of its coefficient.
Therefore the KC expression of equation above is
Kc=[ (Co2)^3 (H2O)^3] / [(C3H6O) (O2)^4)]
Kc =[(1.8^3) x (2.0^3)] / [(0.51) x (0.30^4)] =1.129 x10^4
The reactants are what is put into the reaction equation to get the product. In this case water and ammonia are put into the equation to get the product ammonium hydroxide.
The first choice is the correct answer:
Water and ammonia
Hope this helped!
~Just a girl in love with Shawn Mendes
In order to calculate the new freezing point, we must first find the depression. This is given by:
ΔT = Kf * b * i
where Kf is the cryscopic constant for the solvent, b is the molarity of the solution in moles per kilogram and i is the van't Hoff factor, which tells us how many ions will be released when a substance is dissolved.
Kf = 1.853, b = 1.5, i = 2 (Na⁺ and Cl⁻)
ΔT = 5.5 °C
The new freezing point will be 0 + 5.5
5.5 °C
Protons and electrons i got it right
