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frez [133]
3 years ago
9

Which characteristic best explains the difference in melting behavior of covalent substances and ionic substances?

Chemistry
2 answers:
grin007 [14]3 years ago
7 0

Answer:

C

Explanation:

poizon [28]3 years ago
3 0
Covalent substances have weaker intermolecular attractions.
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What are oil and waters properties of matter?
yulyashka [42]

Answer:

Two other beneficial properties of the oil include the inhibition of corrosion of metal surfaces, such as steel, and the removal of dirt and detritus via detergency.

Properties of water include its chemical formula H2O, density, melting, boiling point & how one molecule of water has two hydrogen atoms covalently bonded to one oxygen atom.

4 0
3 years ago
The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles
sergejj [24]

<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For the general chemical equation:

aA+bB\rightleftharpoons cC+dD

The expression for K_c is given as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical reaction:

2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)

The expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}

The concentration of solid is taken to be 0.

So, the expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

3 0
3 years ago
A cell with osmolarity measuring 300 mosm/l is placed in a beaker that contains a nacl solution with osmolarity of 150mosm/l. pr
tia_tia [17]
<span>My hypothesis is the the cell, having a higher osmolarity than the solution of of nacl in the beaker, will have an osmosis reaction releasing into the solution of nacl. This will continue until both cell and solution reach a balance.</span>
5 0
3 years ago
Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc
densk [106]
<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

                                     = 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

                              = 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

            = (15 g ÷ 17.42 g) × 100 %

            = 86.11%

7 0
3 years ago
Which of the following correctly<br> identifies segment XY and why?
Alecsey [184]

Answer:

sh1t

Explanation:

sh1t yummy

hope this helps

3 0
3 years ago
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