Answer:
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<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2><h2>
_____________________________________</h2><h2>
TRIPLE POINT:</h2>
Triple point is that temperature, at which the substance is found in all three states i.e. solid, liquid and gas. Every substance has different triple point, because Triple point is just above the freezing point and each substance has different freezing and boiling point.
<h2>
_____________________________________</h2><h2>WATER:</h2>
Water has a Melting point or Freezing Point (MP or FP) of
C or 273K and Boiling point (BP)
C or 373 K. Since the triple point is just above the MP or FP thus Triple Point of water is
C or 273.16K.
<h2>
_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
Answer:
the answer is 7 which is the atomic number of nitrogen
Explanation:
Al+Na=24
24/Oxygen (8) =3
3x rounded atomic mass of Ne (3x20) = 60
60+ 20 (# of neutrons in K)=80
80-30 (# of electrons in zinc)= 50
50/25 (the atomic number of Mn)=2
2x9 (number of protons in F)= 18
18+24 (atomic mass of Mg)=42
42/6 (number of neutrons in boron)=7
7 is the atomic number of Nitrogen (N)
Answer:
-2.80 × 10³ kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.
Qcal + Qcomb = 0
Qcomb = - Qcal [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ
where,
C: heat capacity of the calorimeter
ΔT: change in the temperature
From [1],
Qcomb = - Qcal = -29.2 kJ
The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:
ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol
Answer:
Mass = 824.57 g
Explanation:
Given data:
Mass of bromine = ?
Number of moles of bromine = 5.16 mol
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of bromine = 159.8 g/mol
by putting values,
Mass = 5.16 mol × 159.8 g/mol
Mass = 824.57 g