2H2 + O2 ---->2H2O
number of moles in reaction 2 mol 1 mol 2 mol
number of liters in the reaction 2*22.4 L 1*22.4 L 2*22.4L
We can see that volumes of the gases are proportional to coefficients in the reaction ( if gases are under the same conditions), so we can write
2H2 + O2 ---->2H2O
2 L 1 L 2 L
given 40 L ( 25 L) 40 L
We can see that we have excess of O2,
because if 2 L H2 are needed 1 L O2, then 40 L of H2 are needed 20 L O2.
So, limiting reactant is H2, and we will need to calculate Volume of H2O using H2.
2L H2 give 2L H2O(gas), so 40 L H2 give 40 L H2O.
Answer:
loses electrons and loses potential energy.
Explanation:
A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.
Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.
Explanation:
Given the mass of HCl is ---- 0.50 g
The volume of solution is --- 4.0 L
To determine the pH of the resulting solution, follow the below-shown procedure:
1. Calculate the number of moles of HCl given by using the formula:
2. Calculate the molarity of HCl.
3. Calculate pH of the solution using the formula:
Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.
Thus,
Calculation:
1. Number of moles of HCl given:
2. Concentration of HCl:
3. pH of the solution:
Hence, pH of the given solution is 2.47.
I hope this helps! please tell me if it’s wrong.
Answer:
Q=25.7 Kj
Explanation:
76.941 g H2O*1 mol/18.016= 4.27 Mol H20
(4.27 Mol H2O)(6.009 Kj/Mol)
Q=25.7 Kj