Which represents the balanced equation for the beta minus emission of phosphorus-32?
2 answers:
Answer: The correct option is C.
Explanation: Beta minus ( ) decay is the decay in which a neutron is converted into proton and releases beta particle or generally known as electron.
There is an increase in the Atomic number because one protons is being formed.
In the case of beta-minus decay of phosphorous, the P-nucleus gets changed to Sulfur nucleus. The balanced Chemical equation for this process is:
Hence, the correct option is C.
Answer : Option C)
Explanation : The balanced equation for the beta minus decay for emission of Phosphorus-32 is
Where, it is clearly seen that in the beta minus emission a neutron decays into a proton, an electron, and an anti-neutrino.
So, in the phosphorus-32 beta minus decay the product is sulfur-32 along with an electron created from the anti-neutrino.
Therefore, option C is the correct option.
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<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>
To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.
The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.
So, in this case, the balanced reaction is:
6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:
- CO₂: 6 moles
- H₂O: 6 moles
- C₆H₁₂O₆: 1 mole
- O₂: 6 moles
So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:
moles of CO₂= 0.05 moles
Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?
moles of C₆H₁₂O₆= 8.33*10⁻³
Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:
<em>mass of glucose= 1.5 grams</em>
Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>