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Ne4ueva [31]
3 years ago
6

Which represents the balanced equation for the beta minus emission of phosphorus-32?

Chemistry
2 answers:
Agata [3.3K]3 years ago
8 0

Answer: The correct option is C.

Explanation: Beta minus ( \beta ^- ) decay is the decay in which a neutron is converted into proton and releases beta particle or generally known as electron.

There is an increase in the Atomic number because one protons is being formed.

In the case of beta-minus decay of phosphorous, the P-nucleus gets changed to Sulfur nucleus. The balanced Chemical equation for this process is:

^{32}_{15}\textrm{P}\rightarrow ^{32}_{16}\textrm{S}+^0_{-1}\beta

Hence, the correct option is C.

uranmaximum [27]3 years ago
3 0

Answer : Option C) P^{32}_{15} ---> S^{32}_{16} +e^ {0}_{-1}

Explanation : The balanced equation for the beta minus decay for emission of Phosphorus-32 is P^{32}_{15} ---> S^{32}_{16} +e^ {0}_{-1}

Where, it is clearly seen that in the beta minus emission a neutron decays into a proton, an electron, and an anti-neutrino.

So, in the phosphorus-32 beta minus decay the product is sulfur-32 along with an electron created from the anti-neutrino.

Therefore, option C is the correct option.

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The correct answer is C. square planar

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VSEPR theory was first coined by Gillespie  and Nyhlom in 1957 as an improvement over the Sidgwick - Powell theory.

According to this theory, the shape of a molecule is determined by the number of electron pairs that surround the valence shell of the central atom in the molecule.  The electron pairs are positioned as far apart in space as possible to minimize repulsion of electron pairs.

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For a molecule having six electron pairs, an octahedral geometry is expected(electron domain geometry). However, the presence of two lone pairs which are positioned at opposite side of the four single bonds leads to an observed square planar molecular geometry.

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