Answer:
Copper ions are reduced into copper atoms.
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Explanation:
During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.
At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)
Thus the half equation is as follows:
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
20.7 Degree celsius is the temperature of Zippy's room.
Explanation:
The initial conditions of the kookie cola will be depicted by P1,V1 and T1.
P1= 36.5 psi or 2.4816 atm
V1= 355ml or 0.35 L
T1= 275.5K
The final conditions are given P2,V2 and T2
P2= 38.9 psi or 2.6469 atm
V2 = 355 ml or 0.35 L
also the solubility of the carbon dioxide does not change with temperature.
Applying the formula
P1VI/T1=P2V2/T2
since volume does not change and remains constant.
It can be written as:
P1/T1=P2/T2
= 2.4816/275.5=2.6469/T2
T2= 293.85 K
N(H₂O)=1g÷18g/mol=0,055mol
N(H₂O)=0,055mol · 6·10²³ 1/mol (Avogadro number)= 3,33·10²² molecules.