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4 years ago

how do covalent bonds form between atoms?why is it that diatomic molecules always form nonpolar covalent bonds?

1 answer:

5 0

Covalent bonds are formed when two or more non metal atoms share one or more electrons to achieve stable configuration.
Diatomic molecules form non polar covalent bonds because they are linear and the charge distribution across the bond is the same; therefore, resulting in no net charge.

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How many moles are in 2.85x 10^23 atoms of silver

Bingel [31]

Answer:

0.473 moles

Explanation:

(2.85x10e23)/(6.02x10e23) = 0.47342

7 0

4 years ago

Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):

Tom [10]

NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest

4 0

3 years ago

If an atom of an element has a mass number of 45 and it has 20 neutrons in its nucleus, what is the atomic number of the

HACTEHA [7]

Answer:

Explanation:

uestion

If an atom of an element has a mass number of 45 and it has 20 neutrons in its nucleus, what is the atomic number of the

element?

3 0

4 years ago

Ammonia, NH3, can be made by reacting nitrogen and the equation is N2 + 3H2 --> 2NH3 How many moles of NH3 can be made if 18

alukav5142 [94]

N2 + 3 H2 -> 2 NH3
Just use their stoichiometric coefficients (number before the chemical's name) from the balanced chemical reaction to make ratios and solve for the unknown. In this case, 2 moles of NH3 are produced for every 3 moles of H2. Thus, 
7.5 moles H2 x (2 moles NH3 / 3 moles H2) = 5 moles NH3
Thunderclan89

3 0

3 years ago

As an FDA physiologist, you need 0.625 L of phosphoric acid acid / dihydrogen phosphate (H3PO4 (aq) / H2PO4 - (aq) ) buffer with

aksik [14]

Answer:

0.4058L of 1.0M H3PO4

0.2192L of 1.5M NaOH

Explanation:

The pKa of the H3PO4 / H2PO4- buffer is 2.12

To solve this question we must use H-H equation for this system:

pH = pKa + log [H2PO4-] / [H3PO4]

2.75 = 2.12 + log [H2PO4-] / [H3PO4]

0.63 = log [H2PO4-] / [H3PO4]

4.2658 = [H2PO4-] / [H3PO4] (1)

Where [] could be taken as the moles of each reactant

As you have H3PO4 solution, the reaction with NaOH is:

H3PO4 + NaOH → H2PO4- + Na+ + H2O

As you can see, both H3PO4 and H2PO4- comes from the same 1.0M H3PO4 solution

The moles of H3PO4 are:

[H3PO4] = Moles H3PO4 - Moles NaOH

And for H2PO4-:

[H2PO4-] = Moles NaOH added

Replacing in (1):

4.2658 = [Moles NaOH] / [Moles H3PO4 - Moles NaOH]

4.2658 Moles H3PO4 - 4.2658 moles NaOH = Moles NaOH

4.2658 Moles H3PO4 = 5.2658 moles NaOH (1)

In volume:

0.625L = Moles H3PO4 / 1.0M + Moles NaOH / 1.5M

0.625 = Mol H3PO4 + 0.6667 Moles NaOH (2)

Replacing (2) in (1):

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4 / 0.6667)

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4) / 0.6667

4.2658 Moles H3PO4 = 5.2658*(0.9375 - 1.5 mol H3PO4)

4.2658 Moles H3PO4 = 4.9367 -7.8983 mol H3PO4

12.1641 mol H3PO4 = 4.9367

Mol H3PO4 = 0.4058moles * (1L / 1.0moles) =

0.4058L of 1.0M H3PO4

And:

0.625L - 0.4058L =

0.2192L of 1.5M NaOH

5 0

3 years ago