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Sphinxa [80]
4 years ago
6

how do covalent bonds form between atoms?why is it that diatomic molecules always form nonpolar covalent bonds?

Chemistry
1 answer:
Lemur [1.5K]4 years ago
5 0
Covalent bonds are formed when two or more non metal atoms share one or more electrons to achieve stable configuration.
Diatomic molecules form non polar covalent bonds because they are linear and the charge distribution across the bond is the same; therefore, resulting in no net charge.
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The answer should be "Dunes"
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3 years ago
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests tha
lakkis [162]

Answer:

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

Explanation:

Volume of the radiator = 3.6 L

Percentage of antifreeze = 60%

Total volume of anti freeze in radiator = 60% of 3.6 L :

\frac{60}{100}\times 3.6 = 2.16 L

Percentage of water= 40%

Given,optimal cooling of the engine is obtained with only 50% antifreeze.

So, now we want to reduce the percentage of antifreeze from 60% to 50 %

Volume of coolant removed = x

Volume of water added = x

Volume of anti freeze removed = 60% of(x) = 0.6x

Volume of antifreeze left in radiator  =50% of 3.6 L = \frac{50}{100}\times 3.6=1.8 L

1.8 Liter is the desired volume of the antifreeze.

Total volume - Removed volume = desired  volume

2.16 L - 60% of( x) = 1.8 L

2.16 L-0.6x=1.8 L

x=\frac{2.16 l- 1.8 L}{0.6}=0.6 L

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

4 0
4 years ago
What volume of a 0.00945-M solution of potassium hydroxicce would be required to titrae 50.00mL of a sample of acid rain with a
Zepler [3.9K]

<u>Answer:</u> The volume of HBr solution required is 130.16 mL

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=2\\M_1=123\times 10^{-4}M=0.0123M\\V_1=50mL\\n_2=1\\M_2=0.00945M\\V_2=?mL

Putting values in above equation, we get:

2\times 0.0123\times 50=1\times 0.00945\times V_2\\\\V_2=130.16mL

Hence, the volume of KOH solution required is 130.16 mL

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Answer:

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