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Margaret [11]
2 years ago
15

What is the energy of a photon of ultraviolet radiation with a frequency of 4.4 × 1015 hz? planck’s constant is 6.63 × 10–34 j •

s. 2.9 × 10–18 j 2.9 × 10–34 j 2.9 × 10–48 j
Physics
1 answer:
GrogVix [38]2 years ago
8 0

The energy of a photon of ultraviolet radiation is E = 2.91 * 10^-18 J

What is a photon?

A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic energy.

The energy of a photon is obtained by multiplying Planck's constant by the frequency of electromagnetic radiation:

E = h * f

where,

h is Planck's constant

h= 6.63×10⁻³⁴ Js

f= 4.4×10^15 Hz

Substituting the values in the equation for Energy:

E = (6.63×10⁻³⁴) * ( 4.4×10^15)

E = 2.91 * 10^-18 J

Hence,

The energy of a photon of ultraviolet radiation is E = 2.91 * 10^-18 J

Learn more about photon energy here:

<u>brainly.com/question/2393994</u>

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#SPJ4

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