Parta a.
Equation: F = G*m1*m2/d^2
Where
F = 32 N
G = 6.67*10^-11 N.m^2/kg^2
m1 = 9.0*10^13kg
m2 =370 kg
d = distance that separate the center of the two objects.
d^2 = G*m1*m2 / F = 6.67*10^-11 N.m^2/kg^2 * 9.0*10^13 kg *370 kg / 32N = 69,409.69 m^2
d = √69,409.69m^2 = 263.5 m
Part B.
The gravitational field of the comet is g = G*m1/d^2
Notice that it does not depend on the mass of other objects.
Notice also that I will use a distance of 5.0 * 10^3 km, because I think that that is the number that you intended to write in the part b. If that is not the number you can put the right number instead because the solution is written step by step.
g = (6.67*10^-11 N*m^2/kg^2)*(9.0*10^13kg)/(5.0*10^3*10^3m)^2 = 2.4*10^-4 N/kg = 2.4*10^-4 m/s^2
Answer:
Setting short-term and long-term goals is very important to stay on track and motivated to improve fitness levels. You can keep track of your progress by weighing yourself every day to track weight loss, and by steadily increasing the difficulty of the exercises to track your strength improvement. It is very important to reflect on progress, so you can evaluate what you need to do in the future to remain on track, as well as seeing how much you've improved.
By factorys. Because the smoke that builds up from them
Answer:
1.2ms⁻²
Explanation:
F = ma
12 = 10*a
12/10 = a
6/5 ms⁻² = a or 1.2 ms⁻² = a
Answer:
Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.
