Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
The probability of rolling a multiple 2 or a number greater than 3 is 1/3
Since the two numbers vary directly, if Y is quadrupled, X will do the same. 2 times 4 is 8, 15 times 4 is 60.
X = 60.
Hope that helps!! :)
Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
3x-4= - 10
add both side 4 so its a addition property
3x=- 6
now divide both side 3 so it is a <span>division property.
so x=-2</span>
