(a) The coil's self-inductance is 7.26 mH.
(b) The self-induced emf in the coil is 7.26 V
(c) The direction of the induced emf is from b to a.
<h3>Coil's self-inductance</h3>
L = N²μA/I
L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)
L = 7.26 x 10⁻³ H
L = 7.26 mH
<h3>Self-induced emf in the coil</h3>
emf = N(ΔBA)/t
where;
- B is magnetic field
- A is area
- N is number of turns
- t is time
B = μNI/L
B1 = (4π x 10⁻⁷ x 600 x 5)/0.043
B1 = 0.0876 T
B2 = (4π x 10⁻⁷ x 600 x 2)/0.043
B2 = 0.035 T
emf = NΔBA/t
emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)
emf = 7.26 V
The direction of the induced emf is always opposite to the direction of the applied current.
Thus, the direction of the induced emf is from b to a.
Learn more about induced emf here: brainly.com/question/13744192
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