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nataly862011 [7]

2 years ago

8

As the particles in a soup reach the bolling point what happens

1 answer:

ICE Princess25 [194]2 years ago

4 0

Answer:

Once the particles of a liquid reach its boiling point, additional heat would cause the liquid particles to boil off or vaporize.

Explanation:

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When time is measured in days, the decay constant for a particular radioactive isotope is 0.16. Determine the time required for

san4es73 [151]

Answer:

The time take is $t = 1.3964 \ days$

Explanation:

From the question we are told that

The decay constant is $\lambda = 0.16$

The percentage fall is $c = 0.80$

The equation for radioactive decay is mathematically represented as

$N(t) = N_o * e^{- \lambda t }$

Where is $N(t)$ is the new amount of the new the isotope while $N_o$ is the original

At initial $N_o = 100$ % = 1

At $N(t ) = 80$ % = 0.80

$0.80 = 1 * e^{- 0.16 t }$

=> $-0.223 = -0.16 t$

=> $t = 1.3964 \ days$

5 0

3 years ago

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What happens when velocity and acceleration are at right angles to each other

photoshop1234 [79]

You get circular motion, where the acceleration is pointing towards the center of the circle, as long as they are constant, and not fluctuating.

7 0

2 years ago

If a dog ran at 5 m/s how far would it run in 45 s

Virty [35]

Answer:

225 m//s

Explanation:

It ran 5m/s so 5x45=225

3 0

2 years ago

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Do heavier bowling balls go faster than lighter ones?

Effectus [21]

Piper rockelle and I just got off the phone number

7 0

2 years ago

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Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

Sunny_sXe [5.5K]

Answer:

$\mu = 1.645$

Explanation:

By Snell's law we know at the left surface

$\theta_i = 19^o$

$\theta_r = ?$

$\mu_1 = 1$

$\mu_2 = \mu$

now we have

$1 sin19 = \mu sin\theta_r$

$0.33 = \mu sin\theta_r$

now on the other surface we know that

angle of incidence = $\theta_r'$

$\theta_e = 90$

so again we have

$\mu sin\theta_r' = 1 sin90$

so we have

$\theta_r = sin^{-1}\frac{0.33}{\mu}$

$\theta_r' = sin^{-1}\frac{1}{\mu}$

also we know that

$\theta_r + \theta_r' = 49$

$sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49$

By solving above equation we have

$\mu = 1.645$

3 0

3 years ago

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