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2 years ago

As the particles in a soup reach the bolling point what happens

Physics

1 answer:

ICE Princess25 [194]2 years ago

4 0

Answer:

Once the particles of a liquid reach its boiling point, additional heat would cause the liquid particles to boil off or vaporize.

Explanation:

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Leyes de newton primera ley

Nadusha1986 [10]

Answer:

may I know which language

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2 years ago

The surface area of a material is a factor that affects heat conductivity. Does heat flow faster through a large surface area or

Elis [28]

The air flows slower in a bigger space. The air in a small space hit each other heating up, and move faster and faster. is that what your asking?

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3 years ago

5) A parallel series electric blasting circuit consists of 6 branches of 8 caps each. Cap legwire length is 28 ft. The cap circu

andrezito [222]

Answer:

Minimum DC current $= 9$ Ampere

Voltage $= 74.862$ V

Explanation:

Here in this questions three resistors are used in series

Resistance of cap circuit

$R_1 =\frac{ 8* 2.3}{6} \\R_1 = 3.067$

Here $2.3$ is the resistance per cap

Resistance of bus wire

$R_2 = \frac{50 * 4.02 }{1000} \\R_2 = 0.201$

Where $4.02$ is the resistance per $1000$ feet of bus wire of gauge 16

Resistance of firing line

$R_3 = \frac{(2*1000)* 2.525}{1000} \\R_3 = 5.05$

where $2.525$ is the resistance per $1000$ feet of bus wire of gauge 14

Total resistance is equal to

$R = R_1 + R_2 + R_3\\R = 3.067 + 0.201 + 5.05 \\R = 8.318$

Current in firing line is equal to

$1.5 * 6\\= 9$

Voltage is equal to product of resistance and current

$= 9 * 8.318\\= 74.862$

4 0

2 years ago

A 35-year-old patent clerk needs glasses of 50-cm focal length to read patent applications that he holds 25 cm from his eyes. Fi

Natali5045456 [20]

Answer:

28.57 cm

Explanation:

We are given that

Focal length, $f=50 cm$

Distance of application from his eyes,s=40 cm

$\frac{1}{s}+\frac{1}{s'}=\frac{1}{f}$

$\frac{1}{40}+\frac{1}{s'}=\frac{1}{50}$

$\frac{1}{s'}=\frac{1}{50}-\frac{1}{40}=\frac{4-5}{200}$

$s'=\frac{200}{-1}=-200 cm$

s=25 cm

Substitute the values

$\frac{1}{25}-\frac{1}{200}=\frac{1}{f'}$

$\frac{8-1}{200}=\frac{1}{f'}$

$\frac{1}{f'}=\frac{7}{200}$

$f'=\frac{200}{7}=28.57 cm$

6 0

3 years ago

How many LEDs must be combined into one light source to give a total of 3.8 W of visible-light output (comparable to the light o

notka56 [123]

Answer:

This is an incomplete question. The complete question is --

An individual white LED (light-emitting diode) has an efficiency of 20% and uses 1.0 W of electric power.

How many LEDs must be combined into one light source to give a total of 3.8W of visible-light output (comparable to the light output of a 100W incandescent bulb)?

And the answer is --

19 LEDs

Explanation:

The full form of LED is Light emitting diode.

It is given that the efficiency of the LED bulb is 20 %

1 LED uses power = 1 W

So the output power of 1 LED = 0.2 W

We need to find the power required to give a 3.8 W light.

Power required for 3.8 W = Number of LEDs required = (total required power / power required for 1 LED )

= 3.8 / 0.2

= 19

Therefore, the number of LEDs required is 19.

4 0

3 years ago