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AURORKA [14]
3 years ago
12

How does the eye control the amount of light entering it?​

Physics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

the retina of the eye contains photoreceptor cells that detect the light intensity, whether it is dim or bright, changing shape of iris.

Explanation:

in dim light, the receptors detect the light intensity, and in order to allow us to see more clearly, the radial muscles in iris contract, making the pupil widen(dilate), so more light enters eye.

in case of bright light, he receptors detect the light intensity, and in order to allow us to see more clearly, the circular muscles in iris contract, making the pupil narrow(constrict), so less light enters eye

Trava [24]3 years ago
3 0

Answer:

Dilating the pupils.

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30-100=70^3•É+ 30 =3^E
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3 years ago
When the magnetic flux through a single loop of wire increases by , an average current of 40 A is induced in the wire. Assuming
Zielflug [23.3K]

COMPLETE QUESTION:

<em>When the magnetic flux through a single loop of wire increases by </em>30 Tm^2<em> , an average current of 40 A is induced in the wire. Assuming that the wire has a resistance of </em><em>2.5 ohms </em><em>, (a) over what period of time did the flux increase? (b) If the current had been only 20 A, how long would the flux increase have taken?</em>

Answer:

(a). The time period is 0.3s.

(b). The time period is 0.6s.

Explanation:

Faraday's law says that for one loop of wire the emf \varepsilon is

(1). \: \: \varepsilon = \dfrac{\Delta \Phi_B}{\Delta t }

and since from Ohm's law

\varepsilon  = IR,

then equation (1) becomes

(2). \: \:IR= \dfrac{\Delta \Phi_B}{\Delta t }.

(a).

We are told that the change in magnetic flux is \Phi_B = 30Tm^2,  the current induced is I = 40A, and the resistance of the wire is R = 2.5\Omega; therefore, equation (2) gives

(40A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },

which we solve for \Delta t to get:

\Delta t = \dfrac{30Tm^2}{(40A)(2.5\Omega)},

\boxed{\Delta t = 0.3s},

which is the period of time over which the magnetic flux increased.

(b).

Now, if the current had been I =20A, then equation (2) would give

(20A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },

\Delta t = \dfrac{30Tm^2}{(20A)(2.5\Omega)},

\boxed{\Delta t = 0.6 s\\}

which is a longer time interval than what we got in part a, which is understandable because in part a the rate of change of flux \dfrac{\Delta \Phi_B}{\Delta t} is greater than in part b, and therefore , the current in (a) is greater than in (b).

7 0
3 years ago
QUESTION: What is the relationship between the masses of the objects and the gravitational force between them? (Another way of a
OLga [1]

Answer:

As the masses get larger the force gets larger

Explanation:

4 0
3 years ago
How does density affect the behavior of an object in a liquid or a gas?
BlackZzzverrR [31]
According to Archimedes' Principle, an Object's density determines the depth it will get by displacing the liquid or gas molecules... More the density, more it's depth.
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3 years ago
if mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion​
11111nata11111 [884]

Answer:

See explanations below

Explanation:

According to Newtons second law of motion

F = mass * acceleration

F = ma

If mass of an object is decreased to half, then m₂ = 1/2 m

If acting force is reduced by quarter, then F₂ = 3/4 F

F₂ = m₂a₂

3/4F = 1/2m a₂

Divide both expressions

(3/4F)/F = (1/2m)a₂/ma

3/4 = 1/2a₂/a

3/4 = a₂/2a

4a₂ = 6a

2a₂ = 3a

a₂ = 3/2 a

Hence the acceleration of its motion will be one and a half of its original acceleration.

8 0
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