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AURORKA [14]
3 years ago
12

How does the eye control the amount of light entering it?​

Physics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

the retina of the eye contains photoreceptor cells that detect the light intensity, whether it is dim or bright, changing shape of iris.

Explanation:

in dim light, the receptors detect the light intensity, and in order to allow us to see more clearly, the radial muscles in iris contract, making the pupil widen(dilate), so more light enters eye.

in case of bright light, he receptors detect the light intensity, and in order to allow us to see more clearly, the circular muscles in iris contract, making the pupil narrow(constrict), so less light enters eye

Trava [24]3 years ago
3 0

Answer:

Dilating the pupils.

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A force of 12 N changes the momentum of a toy car from 3kgm/s t0 10kgm/s. Calculate the time the force took to produce this chan
yan [13]

Answer:

Time = 0.58 seconds

Explanation:

Given the following data;

Initial momentum = 3 kgm/s

Final momentum = 10 kgm/s

Force = 12 N

To find the time required for the change in momentum;

First of all, we would determine the change in momentum.

Change \; in \; momentum = final \; momentum - initial \; momentum

Change \; in \; momentum = 10 - 3

Change in momentum = 7 kgm/s

Now, we can find the time required;

Note: the impulse of an object is equal to the change in momentum experienced by the object.

Mathematically, impulse (change in momentum) is given by the formula;

Impulse = force * time

Making "time" the subject of formula, we have;

Time = \frac {impulse}{force}

Substituting into the formula, we have;

Time = \frac {7}{12}

Time = 0.58 seconds

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3 years ago
What is the Law of Conservation of Mass and Energy. Fist answer gets brainliest!!←←←←
anzhelika [568]

Answer:The amount if mass of all substances before or after a chemical change are equal

Explanation:

4 0
3 years ago
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A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
andrey2020 [161]

Answer:

The magnitude of force is 1593.4N

Explanation:

The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as

fcostheta + Nsintheta = mv^2/r

Where F = force of friction

Theta = angle of banking

N = normal force

m = mass of car

v = velocity of car

r = radius of curve

The car has no motion in the vertical direction so the sum of forces = 0

The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.

Taking the upward direction to be positive,rewrite the equation above to get:

Ncos thetha = mg - fsintheta =0

Ncistheta = mg + fain theta

N = mg/cos theta + sintheta/ costheta

fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r

Substituting gives:

f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)

Substituting given values into the above equation

f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan

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3 years ago
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Answer:

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Explanation:

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y₀ = 1.13 m

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v = -4.71 m/s

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Answer:

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