All categories

2 years ago

You want to install a 3 yd wide walk around a circular swimming pool. The diameter of the pool is 16 yd. What is

Mathematics

1 answer:

elena-s [515]2 years ago

4 0

3d becauvshsbdbbdhdhdhdhd

You might be interested in

234.A 124/B 136.B 156.D

makvit [3.9K]

I think it’s D. 156 degrees

7 0

2 years ago

Find the y intercept. I already found the slope is 9.

jeka57 [31]

The slope-intercept form: y = mx + b

We have the slope m = 9, therefore: y = 9x + b.

Next. We have the table:

x | -5 | -2 | 1 | 3 | 4 |

y |-46|-19| 8 |26|35|

(1, 8) → x = 1, y = 8

substitute the values of x and y to the equation:

8 = 9(1) + b

8 = 9 + b |-9

b = -1

Answer: y = 9x - 1 → y-intercept is -1.

8 0

2 years ago

PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

7 0

2 years ago

Nine more than half of a number is 21

pogonyaev

I assume you're looking for the number:
0.5n + 9 = 21
- 9
0.5n = 12
÷ 0.5
n = 24
So the beginning number is 24, hope this helps!

3 0

2 years ago

Please find the area of tge triangle help me please asap due tomorrow

Olin [163]

1. Area = 1/2 B(base) x H(height)

2. Area = 1/2 9 x 10

3. Area = 1/2 90

4. Area = 45 inches

8 0

2 years ago

Read 2 more answers