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Brilliant_brown [7]
2 years ago
15

Determine the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution?

Chemistry
1 answer:
UkoKoshka [18]2 years ago
7 0

Taking into account the definition of molarity,  the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 \frac{moles}{liters}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liters}.

<h3>This case</h3>

In this case, you have:

  • number of moles= 30 moles
  • volume= 0.80 L

Replacing in the definition of molarity:

Molarity=\frac{30 moles }{0.80 L}

Solving:

<u><em>Molarity= 37.5 </em></u>\frac{moles}{liters}<em />

Finally, the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 \frac{moles}{liters}.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

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7 0
3 years ago
Sally has constructed a concentration cell to measure Ksp for MCln. She constructs the cell by adding 2 mL of 0.05 M M(NO3)n to
hram777 [196]

Answer:

0.1056 mole

Explanation:

As Sally knows that the charge on the metal ion is n = +2

$MCl_n=MCl_2$

In that compartment $[M^{n+}]=[m^{2+}]=8.279 \ M$

The volume of the $MCl_n$ taken in that compartment = 6.380 mL

So, the number of moles of $M^{2+} = 8.279 \times 6.380$

                                                      = 52.82 m mol

                                                      = 0.05280 mol

$MCl_n \rightarrow M^{n+}+nCl^-$

But n = 2

Therefore, moles of $Cl^-$ = 2 x moles of $M^{n+}$

                                       = 2 x 0.05282

                                       = 0.1056 mole

3 0
3 years ago
slader An experiment is carried out where 13.9 g of solid NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. Dis
kvv77 [185]

Answer:

The mass of the surrounding is M_t = 263.9 \ g

Explanation:

From the question we are told that

      The mass of  NaOH is  m = 13.9 \ g

      The mass of water is m_w = 250.0g

      The chemical equation for the dissociation process is

       NaOH _{(s) } ---> Na^{+}_{(aq)} + OH^{-} _{(aq)}

       The specific heat capacity of the mixture is c_p = 4.18 J g^{-1} C^{-1}

       

The combined mass of the solution is

         M_t = 13 + 250

         M_t = 263.9 \ g

The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is  

  M_t = 263.9 \ g

       

3 0
3 years ago
Why is it important that there is only a small amount of water in the beaker
natita [175]

Answer:

because too much can neutralise the results

4 0
3 years ago
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