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aliina [53]
2 years ago
8

How many moles of NH3 are there in 77.5 g of NH3?

Chemistry
1 answer:
Vanyuwa [196]2 years ago
4 0

Answer:

4.6 (Rounded)

Explanation:

Given: 77.5g of NH3

<u>77.5g of NH3</u>

         1

Plug in your units.

<u>77.5g of NH3</u>    x    <u>         mol of NH3  </u>

         1                                g of NH3

Since we are using grams, find the mass of NH3. To save you time, I'll tell you. It's 17.03052.

Now, plug is number into the equation with 1 on the top because you are trying to find 1 moles worth.

<u>77.5g of NH3</u>    x    <u>     1    mol of NH3  </u>

         1                     17.03052g of NH3

Now solve by multiplying the numbers across.

<u>    77.5x1    </u>    = <u>    77.5    </u>   = 4.55065377.

1x17.03052      17.03052

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Determine physiological temperature, 98.6 F in degree C
Salsk061 [2.6K]

Answer:

37

Explanation:

( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37

4 0
2 years ago
How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
tresset_1 [31]

Answer: 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of AlCl_{3} and \frac{9}{2} moles of H_{2}.

The reaction equation now will be as follows.

3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}

The moles \frac{9}{2} can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

6 0
2 years ago
Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

6 0
2 years ago
Which resources are significantly polluted by heavy metals like mercury?
arlik [135]
<span>Heavy metals like mercury enter waterways by industrial dumping and poor regulatioin of effluent, and they also enter soil through a similar manner, in which waste is disposed of imporperly. Another source of heavy metals are the gases leaving industry carrying these metals. The metals fall as a solid on to soil and water ways. Therefore, the answer is D.</span>
4 0
3 years ago
Read 2 more answers
You are making a 1L solution that you want to be buffered with ammonia and ammonium. However ammonia is a gas that is difficult
zloy xaker [14]

Answer:

54 grams ammonium chloride and 40 grams sodium hydroxide

Explanation:

A buffer is a solution that contains either a weak acid and its salt or a weak base and its salt, the solution is resistant to changes in pH. This means that, a buffer is an aqueous solution of either a weak acid and its conjugate base or a weak base and its conjugate acid.

A Buffer is used to maintain a stable pH in a solution, buffers can neutralize small quantities of additional acid of base. For any buffer solution, there is always a working pH range and a set amount of acid or base that can be neutralized before the pH will change. The amount of acid or base that can be added to a buffer before changing its pH is called its buffer capacity.

A good buffer mixture is supposed to have about equal concentrations of its both components. It is a rule of thumb therefore, that a buffer solution has generally lost its usefulness when one component of the buffer pair is less than about 10% of the other component.

The implication of this is that the ammonium chloride and sodium hydroxide should be of approximately the same concentration. If the masses are dissolved as shown in the answer, then we will have 1molL-1 of each component of the buffer in accordance with the rule of thumb stated above.

4 0
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