During the electrolysis of cryolite ,aluminium and fluorine are formed in.......molar ratio
1 answer:

- From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.
- The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3
<em><u>༒</u></em><em><u>H</u></em><em><u>O</u></em><em><u>P</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>H</u></em><em><u>E</u></em><em><u>L</u></em><em><u>P</u></em><em><u>S</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>༒</u></em>
<em><u>༒</u></em><em><u>M</u></em><em><u>A</u></em><em><u>R</u></em><em><u>K</u></em><em><u> </u></em><em><u>M</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>S</u></em><em><u> </u></em><em><u>B</u></em><em><u>R</u></em><em><u>A</u></em><em><u>I</u></em><em><u>N</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>S</u></em><em><u>T</u></em><em><u>༒</u></em>
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