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3 years ago

During the electrolysis of cryolite ,aluminium and fluorine are formed in.......molar ratio

Chemistry

1 answer:

PtichkaEL [24]3 years ago

8 0

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From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.

The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3

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How do you test a hypothesis using scientific inquiry

irina1246 [14]

Once you have constructed an effective hypothesis, the next step in the scientific inquiry process is to test the hypothesis through experimentation. This is a great opportunity for students to start a science notebook, if they have not yet started recording their progress. Steps to Identifying and Conducting an Appropriate Experiment to Test a Hypothesis 1) Present Hypotheses  Make a list of all potential hypotheses to be tested. 2) Make Predictions  For each hypothesis, ask what would be true if the hypothesis were true. 3) Write the Experimental Procedure  The experimental procedure is a step-by-step recipe for the science experiment. A good procedure contains enough detail that someone else could easily duplicate the experiment. Once you have formed a hypothesis, you will need to develop your experimental procedure to test whether your hypothesis is true or false. 4) Identify the Independent and Dependent Variables  The first step of designing the experimental procedure involves planning how to change the independent variable and how to measure the impact that this change has on the dependent variable. To guarantee a fair test when conducting the experiment, make sure that the only thing changing is the independent variable. All controlled variables must remain constant. 5) Design the Experiments  How can you identify an appropriate experiment that will effectively test your hypothesis? Begin by asking yourselves, “What can I do that will give me one result if my hypothesis is true, and a different result if my hypothesis is false?” Design at least one possible experiment for each hypothesis. Be sure that each experiment tests only one hypothesis.

4 0

4 years ago

While burning coal and charcoal, you notice that coal releases more heat than charcoal. That means that the... 1. elastic energy

Dafna11 [192]

Answer:

3). Chemical potential energy

1). lower in charcoal than in coal.

Explanation:

Chemical potential energy is defined as the energy that can be absorbed or stored in a substance's chemical bonds. It can be released when there is a change in the number of particles of the substance.

As per the question, coal releases more heat than charcoal because 'the chemical potential energy of charcoal is lower than the coal' and hence, the latter would release more heat on burning i.e. the energy that was absorbed in the chemical bonds of the substance. Hence, option 3 and 1 are the correct answers.

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3 years ago

Which statements about a sodium atom (22/11 Na ), are correct?

inysia [295]

Answer:D

Explanation:
Number of electrons=Number of protons
Sodium atom has 1 valence electron

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2 years ago

Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you

Leni [432]

Answer:

a) $\Delta G=2.6kJ$

b) $\Delta G=-979.57kJ$

c) $\Delta G=264.21kJ$

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

$\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol$

So we proceed as follows:

$\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ$

$\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ$

$\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ$

Regards.

6 0

3 years ago

If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3

ss7ja [257]

Answer:- 27.7 grams of $PbI_2$ are produced.

Solution:- The balanced equation is:

$Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3$

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of $Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2$ = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

$28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})$

= $39.0gPbI_2$

$18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})$

= $27.7gPbI_2$

From above calculations, NaI gives least amount of $PbI_2$ , so the answer is, 27.7 g of $PbI_2$ are produced.

8 0

3 years ago

During the electrolysis of cryolite ,aluminium and fluorine are formed in.......molar ratio​

During the electrolysis of cryolite ,aluminium and fluorine are formed in.......molar ratio