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Vika [28.1K]
3 years ago
13

Which object has the greatest velocity? Assume the objects have equal masses.

Chemistry
1 answer:
emmainna [20.7K]3 years ago
5 0
Option c would be the correct answer
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SOVA2 [1]

Answer:

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Explanation:

please a brainliest for tge feedback

7 0
3 years ago
Identify the element symbol<br> 1s22s22p63s23p64s23d104p65s24d5
madam [21]

Answer:

Tc

Explanation:

You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!

5 0
1 year ago
This energy neede to drive photosynthesis???
Andrej [43]
The sun and the rain
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4 years ago
A 25.0 liter rigid container has a mixture of 32.00 grams of oxygen gas and 1 point
Ksivusya [100]

Answer:

P_{T} = 2.94 atm

Explanation:

The total pressure (P_{T}) in the container is given by:

P_{T} = P_{O_{2}} + P_{He}

The pressure of the oxygen (P_{O_{2}}) and the pressure of the helium (P_{He}) can be calculated using the ideal gas law:

PV = nRT

<u>Where</u>:

V: is the volume = 25.0 L

n: is the number of moles of the gases

R: is the gas constant = 0.082 Latm/(Kmol)

T: is the temperature = 298 K

First, we need to find the number of moles of the oxygen and the helium:

n_{O_{2}} = \frac{m}{M}

Where m is the mass of the gas and M is the molar mass

n_{O_{2}} = \frac{32.00 g}{31.998 g/mol} = 1.00 moles  

And the number of moles of helium is:

n_{He} = \frac{8.00 g}{4.0026 g/mol} = 2.00 moles

Now, we can find the pressure of the oxygen and the pressure of the helium:

P_{O_{2}} = \frac{nRT}{V} = \frac{1.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 0.98 atm

P_{He} = \frac{nRT}{V} = \frac{2.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 1.96 atm

Finally, the total pressure in the container is:

P_{T} = P_{O_{2}} + P_{He} = 0.98 atm + 1.96 atm = 2.94 atm

Therefore, the total pressure in the container is 2.94 atm.

I hope it helps you!

6 0
4 years ago
How many atoms are present in 20.9 g of titanium
ZanzabumX [31]

Answer:

atoms Ti = 2.193 E23 atoms

Explanation:

  • 1 mol ≡ 6.022 E23 atoms
  • mm Ti = 47.867 g/mol

⇒ atoms Ti = (20.9 g Ti)×(mol/47.867 g)×(6.022 E23 atoms/mol)

⇒ atoms Ti = 2.193 E23 atoms

5 0
3 years ago
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