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Lina20 [59]
3 years ago
8

A researcher discovers a new bacterium that lives on the seafloor near hydrothermal vents. This organism reduces CO2 to form C6H

12O6 (glucose), and also derives energy from H2 (by oxidation). This bacterium is a:
A. photoautotroph.
B. chemoheterotroph.
C. chemoautotroph.
D. photoheterotroph.
Chemistry
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

C. Chemoautotroph

Explanation:

The new bacterium are able to create their own energy and biological materials  (glucose) from inorganic chemicals (CO2 and H2), therefore they are called chemoautotroph.

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A balloon has a volume of 1.75L at a temperature of 298K. What will be the volume of the balloon if you take it out into the win
lozanna [386]

Answer:

1.52 L

Explanation:

P1V1T2=V2P2T1

V2=V1T2/T1

Fill in with given values then solve

We can check this by knowing that V and T at constant P have a proportional relationship. Hence, this is correct.

- Hope that helped! Please let me know if you need further explanation.

7 0
3 years ago
On July 4, 2020, America turned 7.69 x 10^9
iogann1982 [59]

America's age = 243.85 years

<h3>Further explanation</h3>

When converting units, list and multiply all the units until you find the unit you want

Time unit conversion

1 year = 365 days

1 day = 24 hours

1 hour = 3600 s

7.69 x 10⁹ seconds to years :

\tt =7.69\times 10^9~s\times \dfrac{1`hour}{3600~s}\times \dfrac{1~day}{24~hours}\times \dfrac{1~years}{365~days}\\\\=\dfrac{7.69\times 10^9}{3600\times 24\times 365}\\\\=\boxed{\bold{243.85~years}}

3 0
3 years ago
If you have a density of 3g/ml and volume of 10mL.what is the mass?
ddd [48]
Density = Mass/Volume => Mass = Density*Volume => Mass = 3g/ml*10ml =30g
4 0
3 years ago
Read 2 more answers
By examining data from distant stars, astronomers can determine
Kruka [31]

Answer:

The answer is A ahahahha

Explanation:

Because it just is

8 0
3 years ago
At normal blood pH pH (7.4), hemoglobin is 80 80 % saturated at a partial pressure of oxygen ( O 2 O2 ) of 40 mmHg 40 mmHg . Use
schepotkina [342]

Answer:

An example of oxygen–hemoglobin (O2–Hb) dissociation curves from (A) one penguin at pH 7.5, 7.4 and 7.3, and (B) the emperor penguin, the bar-headed goose (Anser indicus) (Black and Tenney, 1980) and the domestic duck (Anas platyrhynchos, forma domestica) (Hudson and Jones, 1986) at pH 7.4. Note that as for the bar-headed goose, the O2–Hb dissociation curve of the emperor penguin is significantly left-shifted as compared with the domestic duck (and most birds). The bar-headed goose photo is courtesy of Graham Scott; the domestic duck photo is by Maren Winter (licensed under the terms of the GNU Free Documentation License, Version 1.2 or any later version); the penguin photo is by J.M.

Explanation:

The resulting regression equations from the plots of log[SO2/(100–SO2)] vs log(PO2) (all saturation points, all penguins combined) were:

pH 7.5: log[SO2/(100–SO2)] = 2.92589 × log(PO2) – 4.24338 (N=43, r2=0.98, P<0.0001),

pH 7.4: log[SO2/(100–SO2)] = 2.94767 × log(PO2) – 4.39858 (N=70, r2=0.98, P<0.0001),

pH 7.3: log[SO2/(100–SO2)] = 3.04945 × log(PO2) – 4.72019 (N=38, r2=0.99, P<0.0001),

pH 7.2: log[SO2/(100–SO2)] = 3.15958 × log(PO2) – 4.97618 (N=9, r2=0.99, P<0.0001).

5 0
4 years ago
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