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Free_Kalibri [48]
1 year ago
15

A helicopter is 665 feet above the ground. A girl is looking up at the helicopter to form a line. Her line of sight is 5 feet of

f the ground. The distance between the girl and the helicopter is 280 feet.
A helicopter flies 665 feet above ground. What is the measure of the angle of depression from the helicopter to the girl’s line of sight? Round to the nearest degree.
23°
25°
65°
67°
Mathematics
1 answer:
Vilka [71]1 year ago
4 0

The measure of the angle of depression from the helicopter to the girl’s line of sight is 67 degrees.

<h3>What is a right angle triangle?</h3>

A right angle triangle has one of its angle as 90 degrees. The sides and angles can be found using trigonometric ratios.

Therefore, angle of depression from the helicopter can be found as follows:

tan x = opposite / adjacent

where

x = angle of depression

Hence,

tan x = 660 / 280

tan x = 2.35714285714

x = tan⁻¹ 2.35714285714

x = 67.1231281953

x = 67°

Therefore, the measure of the angle of depression from the helicopter to the girl’s line of sight is 67 degrees.

learn more on right triangle here: brainly.com/question/26253402

#SPJ1

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Find an equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0)
Anna007 [38]

The equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0) is 8x -3y = -16

<h3>Equation of a straight line</h3>

From the question, we are to determine the equation of the line parallel to the given equation and that passes through the given point

Lines that are parallel to each other will have the same slope.

First, we will determine the slope of the line in the given equation.

The given equation of the line is

8x − 3y = 1

Express the equation in the slope-intercept form of a line, y = mx + b

Where m is the slope and

b is the y-intercept

That is,

8x − 3y = 1

8x -1 = 3y

3y = 8x - 1

y = 8/3(x) - 1/3

By comparing,

∴ The slope of the line is 8/3

Since we are to find the equation of a line parallel to this, the slope of the line will also be 8/3

Now, find the equation of a line containing the point (-2, 0) and that has  a slope of 8/3

Using the point-slope form of a line

y - y₁ = m(x - x₁)

x₁ = -2

and y₁ = 0

∴ y - 0 = 8/3(x - -2)

y = 8/3(x +2)

3y = 8(x +2)

3y = 8x + 16

8x -3y = -16

Hence, the equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0) is 8x -3y = -16

Learn more on Equation of a line here: brainly.com/question/13763238

#SPJ1

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Please help please help
Dafna1 [17]
Pretty sure it is B?
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