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alina1380 [7]
1 year ago
15

bell canada came by my house that I just bought and installed a new wire support for one of the telphone poles on my property. t

he electrical code says that the support must hit the ground at a 55 degree angle..If the telephone pole is 25 feet tall. how long is the wire spport that bell just installed?
Mathematics
2 answers:
Alika [10]1 year ago
7 0
The cable is going to have to be 40 ft long to be installed
omeli [17]1 year ago
4 0

Answer:

The cable length will have to be at least 30.51936ft

Step-by-step explanation:

c=  \frac{25}{ \sin( 55 ) }  = 30.51936

C = Cable

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Answer:

the answer is 1/12

Step-by-step explanation:

it is 1/12 because if there are only a pair you would have 2 dice. and since each die has numbers all the way up to 6 all you have to do is add them. and don't count all the numbers. like add 1+2+3+4+5+6. that's just plain wrong just do add the highest number on each die (6+6)

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Solve the exponential equation-<br><br> (-5)^2x=625
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Answer:

x=25

Step-by-step explanation:

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What value for n makes this equation true? <br><br> 6 • 25 = (6 • 20) + (6 • n)
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6* 25 = 150 = (6*20= 120) + (6*5=30) Then Add 120+30= 150 so your answer is 5
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3 years ago
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Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

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Step-by-step explanation:

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