Question

Solve for x when {yz} =y^{2}" align="absmiddle" class="latex-formula">

Answer 1

The value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

How to solve for x?

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

$x^{yz} = y^2$

Take the yz root of both sides

$\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}$

Apply the law of indices

$x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}$

Divide yz by yz

$x = \sqrt[yz]{y^2}$

Hence, the value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

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Answer 2

Answer:

e

Step-by-step explanation:

Using euler's identity we can see that e^ipi=-1 and considering that i=y and  i^2=-1 we can conclude that x=e