Solve for x when

Question

2 years ago

12

{yz} =y^{2}" align="absmiddle" class="latex-formula">

2 answers:

Assoli18 [71] · Answer 1 · 2023-03-15T09:13:14+03:00

The value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

$x^{yz} = y^2$

Take the yz root of both sides

$\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}$

Apply the law of indices

$x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}$

Divide yz by yz

$x = \sqrt[yz]{y^2}$

Hence, the value of x in x^yz = y^2 is $x = \sqrt[yz]{y^2}$

Read more about equations at:

#SPJ1

pentagon [3] · Answer 2 · 2023-03-15T10:48:39+03:00

6 0

Answer:

e

Step-by-step explanation:

Using euler's identity we can see that e^ipi=-1 and considering that i=y and i^2=-1 we can conclude that x=e