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Vladimir [108]
2 years ago
12

Solve for x when

{yz} =y^{2}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Assoli18 [71]2 years ago
7 0

The value of x in x^yz = y^2 is x = \sqrt[yz]{y^2}

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

x^{yz} = y^2

Take the yz root of both sides

\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}

Apply the law of indices

x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}

Divide yz by yz

x = \sqrt[yz]{y^2}

Hence, the value of x in x^yz = y^2 is x = \sqrt[yz]{y^2}

Read more about equations at:

brainly.com/question/2972832

#SPJ1

pentagon [3]2 years ago
6 0

Answer:

e

Step-by-step explanation:

Using euler's identity we can see that e^ipi=-1 and considering that i=y and  i^2=-1 we can conclude that x=e

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