The number section A, section B and section C seats sold are 26500, 14200 and 12300 respectively.
<h3>How to use equation to find the total number of seat in each section?</h3>
The stadium has 53,000 seats.
Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C.
The number of seats in Section A equals the total number of seats in Sections B and C.
Therefore,
a = b + c
a + b + c = 53000
b + c + b + c = 53000
2b + 2c = 53,000
25a + 20b + 15c = 1131000
25(b + c) + 20b + 15c = 1131000
25b + 25c + 20b + 15c = 1131000
45b + 40c = 1131000
Hence,
2b + 2c = 53000
45b + 40c = 1131000
40b + 40c = 1060000
45b + 40c = 1131000
-5b = - 71000
b = - 71000 / -5
b = 14,200
Therefore,
2(14,200) + 2c = 53000
2c = 53000 - 28400
2c = 24600
c = 24600 / 2
c = 12300
Hence,
a = b + c
a = 14200 + 12300
a = 26500
learn more on equation here: brainly.com/question/17447452
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