Question

A stadium has 53,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A
equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,131,000 from each sold-out event. How many seats
does each section hold?

Answer 1

The number section A, section B and section C seats sold are 26500, 14200 and 12300 respectively.

How to use equation to find the total number of seat in each section?

The stadium has 53,000 seats.

Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C.

The number of seats in Section A equals the total number of seats in Sections B and C.

Therefore,

a =  b + c

a + b + c = 53000

b + c + b + c = 53000

2b + 2c = 53,000

25a + 20b + 15c = 1131000

25(b + c) + 20b + 15c  = 1131000

25b + 25c + 20b + 15c = 1131000

45b + 40c = 1131000

Hence,

2b + 2c = 53000

45b + 40c = 1131000

40b + 40c  = 1060000

45b + 40c = 1131000

-5b = - 71000

b = - 71000 / -5

b = 14,200

Therefore,

2(14,200) + 2c = 53000

2c = 53000 - 28400

2c = 24600

c = 24600 / 2

c = 12300

Hence,

a =  b + c

a = 14200 + 12300

a = 26500

learn more on equation here: brainly.com/question/17447452

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