Find the value of X. Round to the nearest tenth HELP ASAP!!!!

Mathematics

1 answer:

ZanzabumX [31]2 years ago

7 0

Answer: 22.5

Step-by-step explanation:

$\sin 64^{\circ}=\frac{x}{25}\\\\x=25 \sin 64^{\circ}\\\\x \approx 22.5$

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Let's say we have a circle with a radius of 17 inches. What is the circumference of this circle in inches? Round your answer to

harkovskaia [24]

106.81 is the answer, the formula for this problem is 2*3.14*r, r = radius = 17

8 0

3 years ago

5(x-4)=7x ik its easy just very confused

Dahasolnce [82]

Answer:

- 10

Step-by-step explanation:

Step 1:

5 ( x - 4 ) = 7x Equation

Step 2:

5x - 20 = 7x Multiply

Step 3:

- 20 = 2x Subtract

Step 4:

x = - 20 ÷ 2 Divide

Answer:

x = - 10

Hope This Helps :)

5 0

3 years ago

Read 2 more answers

Ex 4.8 14) integrate 3^(2x-1)

sesenic [268]

Take the integral:

$\large\begin{array}{l} \mathsf{\displaystyle\int\!3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\int\!\frac{1}{2}\cdot 2\cdot 3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^{2x-1}\cdot 2\,dx\qquad(i)} \end{array}$

$\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}$

$\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}$

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$\large\textsf{I hope it helps. :-)}$


Tags: integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

4 0

3 years ago

Is the answer to this D???? U are finding the midpoint again...

Tpy6a [65]

The number between 4 and -7 is -3/2, so no, the answer is (2, -3/2) which is B

8 0

3 years ago

Help please ................

tigry1 [53]

Answer:

187.25

Step-by-step explanation: