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sp2606 [1]
3 years ago
5

Find the slope between the two points given. Then, use the slope and the first point to write the equation of the line in Point-

Slope form. State the slope. Point One: (−4,5) Point Two: (0,0)
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
3 0
M(slope)= -5/4 point-slope(y-y1=m(x-x1)) so it would be y-5= -5/4(x+4)
Lilit [14]3 years ago
3 0

Answer:

y-5=-1 1/4(x+4) or y=-1 1/4x

Step-by-step explanation:

Find the slope of the line (formula: y2-y1/x2-x1)

plug the coordinates and slope into the point-slope formula: y-y₁=m(x-x₁)

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Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)
Allisa [31]

Answer:

Given that we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

From trigonometric identities, we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}

1 -  sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}

1 +  sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

3 0
3 years ago
4(2 - 2 + y)= <br><br> Sorry im bad at math
podryga [215]

Answer:

y = 4

Step-by-step explanation:

Use the distributive property to multiply all terms in the parentheses by 4

You will get (8 - 8  + 4y) = 0

Then, 4y = 0

Divide each side by 4 to get

y = 4

5 0
4 years ago
Read 2 more answers
Set up and solve an equation to find x.
riadik2000 [5.3K]
I would say the equation would be 3x=x+20 and subtract x on both sides and you get 2x=20 so then you would divide both sides by 2 and the answer is 10.
3 0
3 years ago
The area of a circular rose garden is 88<br> square meters.<br> What is the radius of the garden?
masya89 [10]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Give two examples that show how using parentheses can change the order in which operations are performed in an expression
Tom [10]

Yes, parentheses can change the order in which operations are performed in an expression.

Let us understand this with two examples.

First example.

Let us suppose we have to simplify the expression

2\cdot (5-3)\\&#10;=2\cdot 2\\&#10;=4

In this expression we have evaluated subtraction first instead of multiply.

Second example.

Let us suppose we have to simplify the expression

(5\cdot 2)- 3\\&#10;=10-3\\&#10;=7

In this expression we have evaluated multiplication first and then subtraction.

Therefore, from above two examples we can see that  parentheses can change the order in which operations are performed in an expression.

7 0
3 years ago
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