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Leto [7]
3 years ago
10

How do I simplify this? With steps please :)

Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

{ \tt{ =  \frac{ {p}^{2} + 8p + 16 }{ {p}^{2} - 16 } }} \\  \\  = { \tt{  \frac{ {(x + 4)}^{2} }{(x - 4)(x + 4)}  }} \\  \\  = { \tt{ \frac{(x + 4)}{(x - 4)} }}

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I think you mean y in terms of x. You would at +3x to both sides resulting in 5y=30+3x

Step-by-step explanation:

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What property comes first in 2(x+4)=6
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Step-by-step explanation:

That becomes before anything

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The relation R is shown below as a list of ordered
Dmitrij [34]

Answer:

(1, 4) and (1,3), because they have the same x-value

Step-by-step explanation:

For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.

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Therefore, the relation is not a function anymore if both ordered pairs are included.

<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>

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What is 54t x 65f please help me on this question
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3 years ago
Find the equation of the graphed line.
belka [17]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y =  \dfrac{5}{2}x + 5\bigg) \ is \ correct  }}}

<h3><u>Step-by-step explanation:</u></h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

\large\boxed{\orange{\bf y = mx + c} }

We know that slope is \tan\theta. So here slope will be ,

\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}

Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).

\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
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3 years ago
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