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2 years ago

Work is best described as?

Physics

1 answer:

lesya692 [45]2 years ago

5 0

Answer:

Explanation:

In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).

Work is a form of energy, therefore, it is measured in joules.

If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:

W = Ft

W = 10N * 2m

W = 20 Joules

But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.

W = Ft

W = 2N * 10m

W = 20 Joules

And we got the same result.

Work can also be used to calculate power.

Power is equal to P = Work / time

It can also be written as P = delta Work / delta time

Power is measured in joules per second.

With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.

The more powerful one would be the one who managed to make the same work in less time.

Hope it Helped!

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3 years ago

A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t

enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

$v_{avg} = \frac{6000}{20*60}$

$v_{avg} = 5m/s$

now since effect of wind is in opposite direction then we can say

$V_{net} = v_{bird} - v_{wind}$

$5 = 9 - v_{wind}$

$v_{wind}= 4 m/s$

Part b)

now if bird travels in the same direction of wind then we will have

$v_{net}= v_{bird} + v_{wind}$

$v_{net} = 9 + 4 = 13 m/s$

now we can find the time to go back

$time = \frac{distance}{speed}$

$time = \frac{6000}{13}$

$time = 7.7 minutes$

Part c)

Total time of round trip when wind is present

$T = t_1 + t_2$

$T = 20 + 7.7 = 27.7 min$

now when there is no wind total time is given by

$T = \frac{6000}{9} + \frac{6000}{9}$

$T = 22.22 min$

So due to wind time will be more

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4 years ago

R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d

padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

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2 years ago

A bicyclist was moving at a rate of 3 m/s, and then sped up to 4 m/s. If the cyclist has a mass of 100 kg, how much work was nee

kotegsom [21]

Answer:

i got b but urs is a little different tell me if right

Explanation:

i go 100 on my test

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3 years ago

How do you know you are effectively communicating your thoughts to others?

Bond [772]

5 ways to communicate better

Prepare yourself on the subject. ...

Structure your thoughts. ...

Keep it simple. ...

Listen to others with intent. ...

Engage well.

For an individual to succeed as well as for an organization to succeed, effective communication is crucial. Leaders who can articulate their ideas well are better at motivating and forming bonds with their staff. Furthermore, it's critical to positively and concisely convey your opinions.Whether or not communication is successful determines whether a relationship will succeed. Being able to explain your ideas clearly is only one aspect of effective communication; listening intently is another. It is the capacity to completely comprehend, to demonstrate empathy, and to provide feedback in light of the other person's answer. Simply said, it is the fruitful interchange of ideas and opinions between individuals or organizations.

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1 year ago