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1 year ago

State coulomb's law mathematically

Physics

1 answer:

Vsevolod [243]1 year ago

7 0

Coulomb's law is express as:

$\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}$

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Question 8

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2 years ago

Read 2 more answers

A solid sphere with a radius of 50.0 cm has a total positive charge of 40.0 μC uniformly distributed in its volume. Calculate th

il63 [147K]

Answer:

$E=2.88\times 10^5\ N/C$

Explanation:

It is given that,

The radius of the solid sphere, R = 50 cm = 0.5 m

Charge on the sphere, $q=40\ \mu C=40\times 10^{-6}\ C$

We need to find the magnitude of the electric field r = 10.0 cm away from the center of the sphere. The electric field at point r away form the center of the sphere is given by :

$E=\dfrac{kqr}{R^3}$

$E=\dfrac{9\times 10^9\times 40\times 10^{-6}\times 0.1}{0.5^3}$

$E=2.88\times 10^5\ N/C$

So, the electric field 10.0 cm away from the center of the sphere is $2.88\times 10^5\ N/C$ . Hence, this is the required solution.

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3 years ago