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1 year ago

State coulomb's law mathematically

Physics

1 answer:

Vsevolod [243]1 year ago

7 0

Coulomb's law is express as:

$\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}$

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How is copyright infringement similar to plagiarism

Hoochie [10]

Answer:

Copyright infringement is using someone else's work without their permission amd plagiarism is claiming someone else's work as one's own

Explanation:

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3 years ago

A tennis ball is thrown straight up into the air with an initial velocity of 38 m/s.

geniusboy [140]

Answer:

a) 3.9s

b)74m

Explanation:

a) v=u+at

0=38+(-9.8)t

-38=-9.8t

t=-38/-9.8

t=3.877s

t=3.9s

b) s=ut+1/2at²

s=(38×3.9)+1/2(-9.8×3.9²)

s=148.2 -74.529

s=73.671

s=74m

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3 years ago

A drum is struck first with little energy. The drum is then struck with a lot of energy. Which sound will be louder? Why?

Reil [10]

Answer:

The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it

Explanation:

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3 years ago

5 ways in which friction can be useful

saul85 [17]

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3 years ago

A pendulum of length L = [02]____________________ cm and mass m = 169 g is released from rest when the cord makes an angle of 65

arsen [322]

Complete question:

A pendulum of length L = 48.5 cm and mass m = 169 g is released from rest when the cord makes an angle of 65.4° with the vertical. What is the speed of the mass (m/s) upon reaching its lowest point?

Answer:

The speed of the mass upon reaching its lowest point is 2.36m/s

Explanation:

To obtain the speed of the mass upon reaching its lowest point, we apply the principle of conservation of mechanical energy. At the lowest point, the kinetic energy of the pendulum is maximum and at the highest point, the vertical displacement is maximum, thus potential energy is maximum.

Kinetic energy at the lowest point = Potential energy at the highest point

$mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2}v^2\\\\v^2 = 2gh\\\\v =\sqrt{2gh}$

From my explanation above, h is the vertical displacement, when potential energy of the pendulum is maximum. Considering a right angled triangle, this vertical displacement, h is the adjacent of the triangle, and it is equal to

L - Lcosθ.

h = 48.5 - 48.5cos(65.4) = 28.31 cm = 0.2831 m

$v =\sqrt{2gh} = v =\sqrt{2*9.8*0.2831} =2.36 \frac{m}{s}$

Therefore, the speed of the mass upon reaching its lowest point is 2.36m/s

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3 years ago