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3 years ago

The ratio of the speed of light in a medium to the speed of light in a vacuum

Physics

2 answers:

Liula [17]3 years ago

7 0

Answer:D.Refractive Indez

Explanation:

It is usually expressed the other way: the ratio of the speed of light in a vacuum to the speed of light in a medium. In that case, it is called the "index of refraction".

Nina [5.8K]3 years ago

3 0

You're going for "refractive index", but you've got the ratio flipped over.

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I got the correct answer, but I don't know what I did. Why is the answer E?

MariettaO [177]

Explanation:

Displacement is the straight line distance from the starting position to the final position.

Person X walks halfway around circle. So her displacement is 100 m.

Person Y walks 3/4 of the way around. So his displacement is 50√2 m ≈ 70.7 m.

Person Z walks completely around the circle, so their displacement is 0 m.

Therefore:

Z < Y < X

6 0

3 years ago

. A person weighing 750 N gets on an elevator.

Kobotan [32]

F = 750 N (Force)

d = 10 m (displacement )

t = 25 s (time)

L = ? (Mechanical work ) = (Energy)

P = ? (Power)

Solve:

L = F × d = 750 × 10 = 7500 Joules

P = L / t = 7500 / 25 = 300 Watts

5 0

3 years ago

In an experiment what are all the parts of an experiment that remain unchanged are called<br>

stira [4]

The answer for this question is Control Variable because it doesn’t change throughout the experiment.

3 0

3 years ago

Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for e

attashe74 [19]

Answer:

$R=5.2\ \Omega$

Explanation:

In series combination, the equivalent resistance is given by :

$R_{eq}=R_1+R_2+R_3+...$

Let the identical resistors be R. We have, $R_{eq}=15.6\ \Omega$

So,

$R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega$

So, the resistance of each resistor is $5.2\ \Omega$ .

4 0

2 years ago

B.A certain piece of copper wire is determined to have a mass of 2.00 g per meter.

masha68 [24]

Answer:

14cm

Explanation:

Mass per gram of the piece of wire;

2g of the wire is found in 1m

Since

100cm = 1m;

So;

100cm of the wire contains 2g of the wire

To provide 0.28g

Since;

2g of wire is made up of 100cm

0.28g of wire will be contained in $\frac{100 x 0.28}{2}$ = 14cm

14cm of the wire will contain 0.28g

8 0

3 years ago