1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
charle [14.2K]
3 years ago
10

in baseball, a pitcher can accelerate 0.15kg ball from rest to 98 mi/hr in a distance of 1.7m. (a) What is the average force exe

rted on the ball during the pitch? if the mass of the ball is increased, is the force of the required of the pitcher increased, decreased or unchanged?
Physics
2 answers:
Step2247 [10]3 years ago
3 0

Answer:

F=84.68 N

Required force increases

Explanation:

By the equation

v^{2}=u^{2} +2as\\ 98^{2}*1609.344^{2}/(60*60)^{2}=0+2*a*1.7\\a = 98^{2}*1609.344^{2}/((60*60)^{2}*2*1.7)\\a = 564.50m/s^{2} \\

By newton's second law :

F=ma\\F=0.15*564.50  \\F=84.68 N

When the mass increased the force increases as the equation.

F=ma

Serhud [2]3 years ago
3 0

a. The <u>average force exerted</u> on the ball during the pitch is equal to <u>84.68N</u>

b. Since the mass is increased, <u>the force required for the pitcher has to increase too.</u>

Why?

For the first part of the question (a), we need to convert all the units to work with the same system unit.

Converting the speed we have:

1mile=1609.34m\\1hour=3600s

98\frac{mi}{h}*\frac{1609.34}{1mi}*\frac{1h}{3600s}=43.81\frac{m}{s}

Now, calculating the force, we have:

F=mass*acceleration

To calculate the acceleration we can use the following formula:

v^{2} =v_{o}^{2} +2acceleration*distance\\\\acceleration=\frac{v^{2}-v_{o}^{2} }{2distance} \\\\acceleration=\frac{(43.81\frac{m}{s})^{2} -0}{2*1.7m}=\frac{1919.32\frac{m^{2} }{s^{2} } }{3.4m}=564.50\frac{m}{s^{2} } \\\\

Therefore, calculating the force, we have:

Force=mass*acceleration\\\\Force=0.15kg*564.50\frac{m}{s^{2}}=84.68\frac{kg.m}{s^{2}}=84.68N

Hence, we have that the force exerted on the ball during the pich is equal to 84.68 N.

For the second part (b),

We need to assume that the final speed is maintaIned, so, since the equation to calculate the exerted force is a relationship between mass and acceleration (F=ma), if the mass of the object is increased, the force required need to be increased.

Have a nice day!

You might be interested in
A bus starts from village A at 7:00 am and reaches village B at 8:30 am. If the distance between the villages A and B is 60 km.
SVEN [57.7K]

1.1111111111

Explanation:

v=s/t

t=8:30-7:00=1:30

convert to second=5400second

s=60km covert to meter=6000

6000/5400=1.11111111

5 0
2 years ago
Read 2 more answers
Plssss help Do you guys have any other more interesting, funny or creative ideas of incline problems than something sliding down
VashaNatasha [74]
U can always just do the classic roller coaster going up an incline and create some sort of story from that.
8 0
3 years ago
A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista
slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

C' = \frac{1}{2}C

The potential difference across the capacitor is given by

V= \frac{Q}{C}

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

V' = 2 V

Now we can analyze the electric field between the plates of the capacitor, which is given by

E=\frac{V}{d}

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

E'=\frac{2V}{2d}=\frac{V}{d}=E

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

F = qE

Then the force on the particle will stay the same.

4 0
3 years ago
Which of the following determines whether light shining on a metal surface will eject electrons from that surface?
PtichkaEL [24]
From that list, only the frequency makes the difference.

Einstein won his only Nobel Prize for his explanation of this effect.
8 0
3 years ago
A mass of gas under constant pressure occupies a volume of 0.5 m3 at a temperature of 20°C. Using the formula for cubic expansio
Kryger [21]
No cubic expansion given
6 0
3 years ago
Other questions:
  • You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo
    13·1 answer
  • What is the magnification of an astronomical telescope whose objective lens has a focal length of 71 cm and whose eyepiece has a
    8·1 answer
  • Distinguish between the positive and negative influences scientific knowledge can have on society
    13·2 answers
  • Why is it important that a satellite in orbit be above the earth's<br> atmosphere?
    10·1 answer
  • Which of the following describes how the mechanical advantage of a simple machine affects the amount of force needed for work? A
    8·1 answer
  • What is the difference between liquid water and water vapor?
    8·2 answers
  • If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?
    14·1 answer
  • Cellular respiration occurs in the body 24 hours per day. During exercise, the rate of cellular respiration increases. Why does
    7·2 answers
  • An artificial sattelite is moving in a circular orbit of radius 42250km calculate its speed if it takes 24 hours to revolve arou
    7·1 answer
  • An object’s position vs. time graph is a straight line with positive slope, draw the velocity vs. time graph that represents thi
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!