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the "t" variable is independent, namely it can change values "freely", and a(t) is dependent, because it depends on those values on "t" to get its own value.
if we make a table of values for minutes, we know the balloon is inflating at 6000 ft³ each passing minute.
1 minute......................... 6000(1) ft³
2 minutes......................6000(2) ft³
3 minutes......................6000(3) ft³
4 minutes......................6000(4) ft³
t minutes......................6000(t) ft³
before getting in the domain and range, let's find out how much air after 6 minutes.
a(6) = 6000(6)
a(6) = 36000 ft³.
now, what domain, namely values for "t" make sense?
well, we know the balloon can only hold up to 90000 ft³, and on every passing minute is filling up by 6000 ft³, after how many minutes will it be filled up?
90000/6000 = 15, after 15 minutes.
so at 0 minutes, t = 0, the balloon is empty, and 15 minutes later, t = 15, the balloon is filled up, [ 0 , 15 ].
what values for the range, namely a(t), makes sense?
well, we know when the balloon is empty is holding 0 ft³, and when is full it has 90000 ft³, [0 , 90000].
Answer:
Quadratic Formula
so
x = -5
and
x = 0.5
Step-by-step explanation:
Whenever you see a problem in this form, which you will see a lot of, you can try to factor it or use the "least squares" method or what have you, but those won't always work, unfortunately.
Fortunately, the quadratic formula will never fail you with quadratic expressions.
This is the Quadratic Formula
a is the the number on the variable with the exponent ^2
b is the number on the variable with no exponent
c is the third number
a and b cannot be equal to 0; c can be
Since we're looking for a number with an equation that has a square root in it, we're going to get two answers. These two answers come from the radical being separately added AND subtracted from the radical. It's basically two problems.
Plugging in our numbers to this equation gives us x values of -5 and 0.5. This will always work with polynomials with factors of ^2 in them.
If you have a TI-84 calculator or newer, there's a tool on it that will factor polynomials like this one for you just by giving it the numbers.