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Vera_Pavlovna [14]
2 years ago
5

PLEASE HELP ME SOLVE THIS

Mathematics
1 answer:
yan [13]2 years ago
8 0
One to one means only one x value gives one y value

This only happens when x is greater than or equal to -1 [-1, infinity) or when x is less than or equal to -1 (-infinity, -1].

Non decreasing means the slope is zero or positive, so it has to be the first option for the domain [-1, infinity]

The inverse of f(x) = (x + 1)^2
y = (x + 1)^2
x = (y + 1)^2
Sq rt x = y + 1
(sq rt x) - 1 = y
f^-1(x) = (sq rt x) - 1

We cannot take the square root of -1, so the domain of the inverse of f is [0, infinity]
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Which equation can be used to solve the problem? 10 is 50 percent of what number? StartFraction 10 divided by 1 Over 50 divided
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6+8=4k-.5k
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Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke
drek231 [11]

Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

A=r^{2}\pi

Where<em> r</em> is the radius of the circle.

2. The diameter of a circle is:

D=\frac{r}{2}

Where <em>r</em> is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a  50-meter keck telescope is:

A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}

4. And the light-collecting area of a 10-meter keck telescope is:

A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}

5. Divide A_1 by A_2, then:

\frac{1963.49m^{2}}{78.53m^{2}}=25

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

4 0
4 years ago
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