Answer:
x1 = 275 miles (shorter)
x2 = 318 miles (longer)
Step-by-step explanation:
Let
x1 = be the shorter route
v1 = speed of the car in the shorter route
t1 = time it took to cover shorter route
x2 = the longer route
v2 = speed of the car in the longer route
t2 = time it took to cover longer route
x1 + 43 = x2 (1)
v2 = v1 -2 (2)
v2 = x2/t2 = x2/6
v1 = x1/t1 = x1/5
This means that
v2 = v1 -2 =>
x2/6 = x1/5 -2
The system of equations results
a. x1 -x2 = -43
b. x1/5 - x2/6 = 2
Solving this system of equations, we find that
x1 = 275 miles
x2 = 318 miles
5/8 is more than 11/20
If we find the lower common multiple of the denominators which is 160 then we can multiply the top numerators by the opposite denominators
5x20=100
11x8=88
We now have

The one on the left is simplified to 5/8 and the right is simplified to 11/20
What is this question asking


keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference