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FinnZ [79.3K]
2 years ago
15

The pressure of a sample of gas is measured at sea level with an open-end mercury manometer, and the liquid level is 13.7 cm hig

her on the left side than the liquid level on the right side (assume the gas chamber is on the left side).
Assuming atmospheric pressure is 760.0 mm Hg, determine the pressure of the gas in mm Hg.


83.1 mmHg


623 mmHg


0.820 mmHg


83,100 mmHg
Chemistry
1 answer:
docker41 [41]2 years ago
7 0

The manometer is the device used to measure the pressure exerted by the gas and the liquids. At a pressure of 760 mmHg, the pressure of a gas is 623 mm Hg. Thus, option b is correct.

<h3>What is a manometer?</h3>

A manometer is an instrument used to estimate the pressure of the gauge and not the atmosphere.

Given,

Atmospheric pressure (P atm) = 760 mmHg

Height of the mercury column (P Hg) = 137 mm Hg

Substituting values,

P atm = P gas + P Hg

P gas = P atm - P Hg

P gas = 760 mm Hg - 137 mm Hg

= 623 mm Hg

Therefore, option b. 623 mm Hg is the pressure of the gas.

Learn more about manometer here:

brainly.com/question/17166380

#SPJ1

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A 200.0mL closed flask contains 2.000mol of carbon monoxide gas and 2.000mol of oxygen gas at the temperature of 300.0K. How man
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There will react 0.400 moles of oxygen.

Explanation:

<u>Step 1:</u> Data given

Volume of the closed flask = 200.00 mL = 0.2 L

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Number of moles of O2 = 2.000 mol

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Pressure decreases with 10%

<u>Step 2</u>: The balanced equation

2CO(g)+O2(g)⟶2CO2(g)

<u>Step 3</u>: Calculate the initial pressure of the flask before the reaction

P = nRT/V

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⇒ R is gas constant (0.08206 atm*L/mol*K)

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<u>Step 4:</u> When the pressure is 10 % decreased:

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<u>Step 5:</u> Calculate the number of moles

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⇒ with n = the number of moles

⇒ with P = the pressure = 443.124 atm

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⇒T = the  temperature = 300.0K

n =(443.124*0.2)/(0.08206*300)

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<u>Step 6:</u> Calculate number of moles

For the reaction :2CO(g) + O₂(g) ⟶ 2CO₂(g)

For each mole of O2 we have 2 moles of CO, to produce 2 moles of CO2

Moles CO = (2 -2X) moles

Moles O2 = (2-X) moles

Moles CO2 = 2X

The total number of moles (4 -X)= 3.6 moles

Where X are moles that react

X = 0.400 moles

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