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FinnZ [79.3K]
2 years ago
15

The pressure of a sample of gas is measured at sea level with an open-end mercury manometer, and the liquid level is 13.7 cm hig

her on the left side than the liquid level on the right side (assume the gas chamber is on the left side).
Assuming atmospheric pressure is 760.0 mm Hg, determine the pressure of the gas in mm Hg.


83.1 mmHg


623 mmHg


0.820 mmHg


83,100 mmHg
Chemistry
1 answer:
docker41 [41]2 years ago
7 0

The manometer is the device used to measure the pressure exerted by the gas and the liquids. At a pressure of 760 mmHg, the pressure of a gas is 623 mm Hg. Thus, option b is correct.

<h3>What is a manometer?</h3>

A manometer is an instrument used to estimate the pressure of the gauge and not the atmosphere.

Given,

Atmospheric pressure (P atm) = 760 mmHg

Height of the mercury column (P Hg) = 137 mm Hg

Substituting values,

P atm = P gas + P Hg

P gas = P atm - P Hg

P gas = 760 mm Hg - 137 mm Hg

= 623 mm Hg

Therefore, option b. 623 mm Hg is the pressure of the gas.

Learn more about manometer here:

brainly.com/question/17166380

#SPJ1

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Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

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Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

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p_i = partial pressure of gas

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p_{He}=X_{He}\times p_T

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Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

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