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3 years ago

How do I balance this equation? (Number 2)

Chemistry

1 answer:

Nikitich [7]3 years ago

5 0

Answer:

6AgI +Fe2(CO3)3 = 2FeI3 + 3Ag2CO3

Explanation:

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Answer the following question: Ethanol, C2H5OH, is considered clean fuel because it burns in oxygen to produce carbon dioxide an

musickatia [10]

127.88 grams of ethanol were present at the beginning of the reaction
Explanation:
Firstly, let's make the combustion reaction:
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
By 1 mol of ethanol, you can make 3 mole of water.
Mole of water = Water mass / Molar mass
150g / 18g/m = 8.3 mole
3 mole of water came from 1 mol of ethanol
8.3 mole came from (8.3 .1)/3 = 2.78 mole of ethanol
Molar mass ethanol = 46 g/m
Mole . molar mass = mass
2.78 m . 46g/m = 127.88 g

3 0

3 years ago

The polar nature of water molecules gives water many unique properties. Which of these statements is NOT true regarding the prop

inessss [21]

B) Water only dissolves other non-polar molecules.

<em>This option is wrong because water is a polar molecule and it can dissolve only other polar molecules.</em>

6 0

4 years ago

Read 2 more answers

Which statements describe surface waves? Check all that apply.

neonofarm [45]

Answer:

The correct answers are "They travel slower than P waves", "They result in much ground motion" and " They are produced by P and S waves".

Explanation:

A surface wave can travel through the existing interface between Earth and air, as well as between Earth and water. A clear example of this type of waves are Love and Rayleigh waves. They travel slower than primary waves, produce large movements in the ground and are produced by primary and secondary waves.

Have a nice day!

3 0

3 years ago

A 1.11 g sample of caffeine, C8H10N4O2, burns in a constant-volume calorimeter that has a heat capacity of 7.85 kJ/K. The temper

VladimirAG [237]

Answer:

401135 kJ

Explanation:

From the balanced quation,

(q/n) = CΔE

Molar heat of combustion = 7.85kJk × (303.81-298.70)k

= 7.85kj × 5.11

= 40.1135kj

4 0

3 years ago

Rank the species CH2NH, CH3I, HF, C2H6 from most to least miscible in ammonia (NH3) 1. CH3I > C2H6 > HF > CH2NH 2. CH2N

777dan777 [17]

Answer:

$HF>CH_{2}NH>CH_{3}I>C_{2}H_{6}$

Explanation:

$NH_{3}$ is an weak base. HF is an weak acid. Hence an acid-base reaction will ocuur between $NH_{3}$ and HF resulting a homogeneous mixture.

$NH_{3}$ is a polar protic molecule. Hence it can form hydrogen bonding with another polar protic molecule $CH_{2}NH$ . Also dipole-dipole attraction force along with london dispersion force exists between $CH_{2}NH$ and $NH_{3}$ .

$CH_{3}I$ is a polar molecule. Hence only dipole-dipole attraction force along with london dispersion force operates between $CH_{3}I$ and $NH_{3}$ .

$C_{2}H_{6}$ is a non-polar molecule. Hence only london dispersion force exists between $C_{2}H_{6}$ and $NH_{3}$ .

So, order of miscibility: $HF>CH_{2}NH>CH_{3}I>C_{2}H_{6}$

(most) (least)

5 0

3 years ago