Answer:
We need 1.714 moles N2
Explanation:
Step 1: Data given
The reaction yield = 87.5 %
Number of moles NH3 produced = 3.00 moles
Step 2: The balanced equation
N2(g)+ 3H2(g) →2NH3(g)
Step 3: Calculate moles N2
For 2 moles NH3 produced we need 1 mol N2 and 3 moles H2
This means, if the yield was 100%, for 3.00 moles NH3 produced , we need 1.5 moles N2
For a 87.5 % yield:
we need more N2, increased by a ratio of 100/87.5.
100/87.5 * 1.5 = 1.714 moles N2
Hydrogen is grouped with the alkali metals because they are grouped based on their properties and behavior, and like the other elements in Group 1 (1A), it only has one valence.
Yes, that is true. in order for it to be a redox reaction, both oxidation and reduction must be occurring.
The correct answer is option A.
D = M/V
The density of a substance is the ratio of its mass to its volume.
Density = mass / volume
or D = M/V
The unit of density is gram per milliliter or g/ml, when mass is expressed in gram or g and the volume is expressed in milliliter ml.
If we know the mass and volume of a substance we can calculate its density using the formula for density.
Answer : The pH of the solution is, 2.67
Explanation :
The equilibrium chemical reaction is:
Initial conc. 0.450 0 0
At eqm. (0.450-x) x x
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
The concentration of 
= x = 0.00212 M
Now we have to calculate the pH of solution.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
Therefore, the pH of the solution is, 2.67
