Valence Electrons are The number of electrons in the outer most shell of an atom. These shells have a maximum amount before being filled by electrons, in which remaining electrons will fill the next remaining valence shell.
I think this is what your talking about.
Answer: The correct answer is option (A).
Explanation:
Oxidation : A chemical reaction in which addition of oxygen occurs or removal of hydrogen occurs is called oxidation.
Reduction:A chemical reaction in which elimination of oxygen occurs or addition of hydrogen occurs is called reduction.
In a given reaction,:
- The glucose molecule is getting oxidized into carbon-dioxide. Before oxidation in glucose molecule ratio of carbon and oxygen atom was 1:1 which changes to 1:2 after oxidation of glucose into carbon-dioxide.
Hence, is getting oxidized.
- The oxygen molecule is reduced because addition of hydrogen atoms are taking place in oxygen molecules which gives water after reduction.
Hence, is getting reduced.
So, correct answer is option (A).
<span>Answer:
A 1.00 L solution containing 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en).
contains
0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts with twice as many moles of en = 0.000600 mol of en
so, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted = 0.00180 mol en remains
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts to form an equal 0.000300 moles of Cu(en)2^2+
Kf for Cu(en)2^2+ is 1x10^20.
so
1 Cu+2 & 2 en --> Cu(en)2^2+
Kf = [Cu(en)2^2+] / [Cu+2] [en]^2
1x10^20. = [0.000300] / [Cu+2] [0.00180 ]^2
[Cu+2] = [0.000300] / (1x10^20) (3.24 e-6)
Cu+2 = 9.26 e-19 Molar
since your Kf has only 1 sig fig, you might be expected to round that off to 9 X 10^-19 Molar Cu+2</span>
Yes the water boils but it doesn't become water gas it becomes just gas also known as evaporation