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3 years ago

Rewrite 1/5:1/2 as a unit rate

Mathematics

1 answer:

yulyashka [42]3 years ago

4 0

Hey there! I'm happy to help!

The unit rate is how much stuff there is per 1 unit. All ratios can be rewritten as fractions, this one could be 0.2/0.5. The word per means divide, and fractions are basically dividing. So, we want the denominator to be 1.

To get 0.5 to 1, we multiply by 2. So, we will multiply the fraction by 2/2.

0.2/0.5(2/2)=0.4/1

Therefore, the unit rate is 0.4/1 or 0.4:1 or 0.4 per 1.

Have a wonderful day! :D

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At the age of 20 weeks, Zoe weighed 16 lb 4 oz. Her birth weight was about 33 1/3% of her 20- week weight. To the nearest ounce,

Tanzania [10]

B=(100/300)(16*16+4)

b=(100/300)260

b= 86 2/3 oz

b=87 oz (to nearest oz)

4 0

3 years ago

Help Please One Mixed Fraction 1/2 x 1 4/9

adoni [48]

Answer:

13/2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Evaluate each function following the specification.

telo118 [61]

Answer:

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

$\#4 \ a. \ h(-1) = \dfrac{1}{3}, \ h(0) =0, \ h(2) = \infty$

b. Yes, x ≠ 2

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of g can take any value of x which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

$h(x) = \dfrac{x}{x - 2}$

By substitution, we get;

$h(-1) = \dfrac{-1}{(-1) - 2} = \dfrac{-1}{-3} = \dfrac{1}{3}$

$\therefore h(-1) = \dfrac{1}{3}$

$h(0) = \dfrac{0}{0 - 2} = \dfrac{0}{-2} =0$

$\therefore h(0) =0$

$h(2) = \dfrac{2}{2 - 2} = \dfrac{2}{0} = \infty$

$\therefore h(2) = \infty$

$h(-1) = \dfrac{1}{3}, \ h(0) =0, \ h(2) = \infty$

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for x in the function, which is x ≠ 2

3 0

3 years ago

N is a positive integer

Murrr4er [49]

Part (1)

n is some positive integer. Let's say for now that n is even. So n = 2k, for some integer k

This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

where m = k(2k-1) is an integer

The result 2m is even showing that n(n-1) is even

------------

Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

Now multiply n and n-1

n(n-1) = (2k+1)(2k) = 2k(2k+1) = 2m

where m = k(2k+1) is an integer

We've shown that n(n-1) is even here as well.

------------

So overall, n(n-1) is even regardless if n is even or if n is odd.

Either n or n-1 will be even. If you multiply an even number with any number, the result will be even.

=======================================================

Part (2)

n is some positive integer

2n is always even since 2 is a factor of 2n

2n+1 is always odd because we're adding 1 to an even number. The sequence of integers goes even,odd,even,odd, etc and it does this forever.

-----------

Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

The 0.5 at the end is not an integer, so there's no way that (2n+1)/2 is an integer; therefore 2n+1 is odd.

6 0

2 years ago

Find all x and y intercepts of the graph of the function f(x)= 2x^3+6x^2-2x-6

topjm [15]

9514 1404 393

Answer:

y-intercept: (0, -6)
x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

f(x) = (2x^3 +6x^2) -(2x +6)

f(x) = 2x^2(x +3) -2(x +3)

f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

4 0

2 years ago