Answer:
I think its c I'm not sure
Answer:
12. 5(5x+4)(5x-4)
13. 2(4v+5)(4v-5)
14. 5(3x+2)(3x-2)
Step-by-step explanation:
Answer:
The temperature difference relative to the high temperature is -2°F.
Step-by-step explanation:
We are given that the temperature started at 35°F. The temperature went down 4°F and then up 2°F.
Firstly, the original temperature = 35°F
Now, it is stated that the temperature went down 4°F, this means that the temperature decreases by this amount.
So, the new temperature = 35°F - 4°F = 31°F
Now, the temperature went up by 2°F, this means that the temperature increases by this amount.
So, the final temperature = 31°F + 2°F = 33°F
Now, the final temperature difference relative to the high temperature is given by = 33°F - 35°F = -2°F.
{Here, the maximum temperature is 35°F}
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
The answer is 16 because u need to subtract the largest and the lowest
