7.50
25% also equals 1/4 so divide 130.00 by 4 which equals 32.50
subtract 32.50 from 130.00 which equals the cost, 97.50
97.50 minus 90$ is 7.50, therefore that is the answer
It's not clear whether you meant 30n^(2b) or [30n^2] b.
I will assume the latter.
b can then be factored out of all three terms, resulting in
b [30n^2 - 87n + 30] = b [ 3 ] [10n^2 - 29n + 10 ]
Can you factor this further?
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Answer:
A. 46.71
Step-by-step explanation:
I'm going to guess this is a "free-point" question, but here we go.
46.7 can be represented as 46.70, so, understandibly, adding 1 to the hundreths place gives you.
46.71
Hope this helps!
