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Korolek [52]
2 years ago
15

Given the algebraic expression the quantity 64 times x to the two-thirds power end quantity to the negative one-third power comm

a, create an equivalent expression.
1 divided by the quantity 4 times x to the one-third power end quantity
1 divided by the quantity 4 times x to the two-ninths power end quantity
4 times x to the one-third power
4 times x to the two-ninths power
Mathematics
1 answer:
11111nata11111 [884]2 years ago
3 0

The given algebraic expression is equal to 1 divided by the quantity 4 times x to the two-ninths power end quantity. The correct option is B.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The given algebraic expression can be simplified using the exponential properties. Therefore, the simplification of the algebraic expression can be done as shown below.

(64x^{\frac23})^{-\frac13}

= (4^3)^{-\frac13} \times x^{(\frac23 \times -\frac13)}\\\\= 4^{(3 \times -\frac13)} \times x^{(\frac23 \times -\frac13)}\\\\= 4^{-1} \times x^{-\frac29}\\\\=\dfrac{1}{4x^{\frac29}}

Hence, the correct option is B.

Learn more about Expression here:

brainly.com/question/13947055

#SPJ1

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After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum
Svetlanka [38]

Answer:  40000

Step-by-step explanation:

The formula to find the sample size is given by :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2, where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. n\ \alpha\ \dfrac{1}{E^2}

By the equation inverse variation, we have

n_1E_1^2=n_2E_2^2

Given : E_1=0.05   n_1=1000

E_2=0.025

Then, we have

(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000

Hence, the sample size will now have to be 4000.

6 0
3 years ago
What is 6/4 as a mixed number?
CaHeK987 [17]
1.5 because 6 goes in to 4 1.5 times


8 0
3 years ago
(9·20+60)÷4−16+4·(20·5)
neonofarm [45]

\text {Hello! Let's Solve this Problem!}

\text {The First Step is to Solve the Parentheses:}

\text {90*20=180+60=240}\\\text {20*5=100}

\text {Your new Problem should be: 240/4-16+4+100}

\text {The Next Step is to Divide:}

\text {240/4=60}

\text {Your new Problem should be: 60-16+4*100}

\text {The Next Step is to Subtract:}

\text {60-16=44}

\text {Now the Next Step is to Multiply:}

\text {4*100=400}

\text {The Final Step is to Add:}

\text {44+100=}

\text {Your Answer should be:}

\fbox {444}

\text {Best of Luck!}

\text {-LimitedX}

6 0
3 years ago
Read 2 more answers
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
Scrat [10]

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


ax + by = a^2 + b^2


ax + by -( a^2 + b^2) = 0


That's standard form; let's plug in the numbers:


4 x - 4 y - 32 = 0


x - y - 8 = 0



5 0
3 years ago
Whats an equation slop 0.5, passes through(6,4)
4vir4ik [10]

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies 0.5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=0.5(x-6) \\\\\\ y-4=0.5x-3\implies y=0.5x+1

5 0
3 years ago
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