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Ipatiy [6.2K]
2 years ago
9

4m^2-5m when m= -4 solve

Mathematics
1 answer:
yawa3891 [41]2 years ago
8 0

Answer:

84

Step-by-step explanation:

4 (-4)^2 - 5(-4)

4 × 16 - 5 × -4

64 + 20

84

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0.402,0.42,0375,12<br> Order from least yo greatest
Neko [114]

Answer:

0.402, 0.42, 12, 375

6 0
3 years ago
If I have a candy bar divided into 6 equal parts, and I eat 2 of the parts, what fraction of the candy bar did I eat?
Afina-wow [57]

Answer:

2/6 or 1/3

Step-by-step explanation:

Nothing it is just basic mathematics

6 0
3 years ago
Read 2 more answers
Find the area of the shaded region .
klasskru [66]
Area of the shaded region=area of the greater rectangle- area of the inner rectangle.

Area of a rectangle=length x width.

Area of the greater rectangle=(8x-1)(6x)
area of the inner rectangle=(5x+3)(2x)

Area of the shaded region=(8x-1)(6x)-(5x+3)(2x)
=48x²-6x-(10x²+6x)
=48x²-6x-10x²-6x
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Answer: the area of the shaded region would be: 38x²-12x
8 0
4 years ago
Need help with 4-10 pleaseeee
emmainna [20.7K]

Answer:

-6

Step-by-step explanation:

10 - 4 = 6

Turn it to negative.

-6

5 0
4 years ago
PLEASE!!!!!!!!!! HELP NEEDED QUICK
Triss [41]
We have to find the expected value for the PlayBall lottery. 
The price of the ticket = $1
Prize amount = $250
If a player wins, he will be winning $249 as the price is not paid back along with the prize amount. He is spending $1, getting back $250, so the net amount he is getting back is $249.

Now we have to find the probability of winning and losing.

Number of letters from A to T = 20
Number of digits from 0 to 9 = 10

Probability of picking up the same letter that was picked on that day = 1/20
Probability of picking up the same number that was picked on that day = 1/10

Thus, the Probability of picking up the same letter and same number that was picked on that day = \frac{1}{20}* \frac{1}{10}= \frac{1}{200}

Thus, the probability of winning = 1/200

The probability of losing = 1- \frac{1}{200}=\frac{199}{200}

The expected value E for the PlayBall lottery will be:

E= \frac{1}{200}(249)- \frac{199}{200}(1) \\  \\ &#10;E= \frac{1}{4}  \\  \\ &#10;E=0.25

Thus, the option C gives the correct answer
4 0
4 years ago
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