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stealth61 [152]
2 years ago
9

What is the shape of the cross section taken parallel to the base of a cylinder? circle rectangle triangle ellipse

Mathematics
1 answer:
Naya [18.7K]2 years ago
5 0

The option A is correct. A circle is the shape of the cross section taken parallel to the base of a cylinder.

According to the statement

We have given that the cylinder and we have to tell that the which shape required for the cross section taken parallel to the base of a cylinder.

So, For this purpose,

We know that the

A cylinder is a three-dimensional solid, one of the most basic geometric shapes.

In this shape the surface formed by the points at a fixed distance from a  line segment, which is  known as the axis of the cylinder.

As the bases of cylinder are two identical circles which are parallel to the curved surface.

The curved surface when we open will be circle rather than the circle.

So, Due to this reason the answer is a circle.

Therefore, a circle is the shape of the cross section taken parallel to the base of a cylinder.

Learn more about base of cylinder here

brainly.com/question/76387

#SPJ1

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\dfrac{-2}{3} \div 2\dfrac{1}{4} = <br> 3<br> −2<br> ​ <br> ÷2 <br> 4<br> 1<br> ​
bekas [8.4K]

Answer:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

Step-by-step explanation:

Given

\dfrac{-2}{3} \div 2\dfrac{1}{4} =

Required

Solve

Start by converting the mixed number to improper fraction

\dfrac{-2}{3} \div \dfrac{9}{4} =

Convert the division to muliplication

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\dfrac{-2*4}{3*9}=

\dfrac{-8}{27}

Hence:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

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