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n200080 [17]
3 years ago
11

Please help with this math question will mark you brainiest

Mathematics
1 answer:
kati45 [8]3 years ago
8 0

Answer: MO is 16

Step-by-step explanation:

I did a really really long solution. But the short version is 9x-20=16 because they’re both MO they shud be equal to each other. Then you get that x is 4.

Then plug 4 in for 3x-4 which is 8.

And then also plug 4 in for 9x-20 which looks like 9(4)-20, you get 16

The answers 8 is the half of 16 just like in the diagram where ZX IS THE HALF OF MO.

P.s I used 3x-4 for zx which is the half of MO because zx and yX are congruent to each other(they have the same length).

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Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

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Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

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b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

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7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

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c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

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Using calculator :

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= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

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