2 years ago

What is the twentieth term in the sequence 23, 43, 63, 83 …?

Mathematics

1 answer:

gogolik [260]2 years ago

8 0

Answer:

403

Step-by-step explanation:

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Given ΔABC with A(–4, –2), B(4, 4), and C(18, –8), write the equation for the line containing median segment The term is line se

Monica [59]

Here we want to find the equation of the line containing the median CP.

P, being the midpoint of AB can be found using the midpoint formula as:

$\displaystyle{ P=( \frac{-4+4}{2} , \frac{-2+4}{2} )=(0, 1)$ .

The slope m of the line through CP can be found by the slope formula using points C(18, -8) and P(0, 1):

$\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{-8-1}{18-0}= \frac{-9}{18}= \frac{-1}{2}$ .

Now, we can write the equation of the line with slope -1/2, passing through
P(0, 1):

$y-1= \frac{-1}{2}(x-0)\\\\y= -\frac{1}{2}x+1$ .

Answer: $y=-\frac{1}{2}x+1$

5 0

3 years ago

What is the exact area of a circle with a diameter of 18 feet

marin [14]

A = π r^2
A = 9^2 <span>π
</span>A = 81<span>π

if using </span>π = 3.14 then

A = 3.14 x 81 = 254.47 ft^2

answer: 81π ft^2 or 254.47 ft^2

hope that helps

6 0

3 years ago

Help Please! Find The Missing Sides Using Special Right Triangles.

matrenka [14]

Answer:

Choice 1

Step-by-step explanation:

m^2 +n^2=13^2

m^2=13^2-n^2

n^2=13^2-m^2

Both m & n =(13 x sq rt 2)/2

To put it another way:

m=(sq rt 2)/2 x 13

n=(sq rt 2)/2 x 13

6 0

3 years ago

At a rock concert, the ratio of girls to boys is 3:7. If there are 360 more boys than girls, how many girls are at the concert?

bixtya [17]

You could understand the ration as parts: the total number of parts was 3+7=10.

So girls were 3/10 parts and boys 7/10 parts. The difference was 7-3=4 parts. this difference is equal to 360, so each part is 90 (4*90 =360).

so girls are "3 parts" and each part is 90, then the number of girls is 3*90=270.

4 0

3 years ago

Find 2 2/3 / 4 1/3 . Simplify the answer and write as a mixed number if appropriate.

Delvig [45]

2 2/3 ÷ 4 1/3 = 8/13

8 0

3 years ago

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