(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ =
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Answer: 30
Step-by-step explanation:
21+39/2
=30
Answer:
x = -33
Step-by-step explanation:
2/3(x+6) = -18
multiply (x+6) by 2/3
2/3x + 4 = -18
subtract 4 from both sides
2/3x + 4 - 4 = -18 - 4
2/3x = -22
multiply by 3/2
2/3 x 3/2 x = -22 x 3/2
x = -33
Hello there!
To start off this problem, let's replace f(x) with x in the equation. This gives us the following.

Subtract 3/4*x from both sides.



Now, multiply both sides by 4 to eliminate the fraction on the left side.

Your answer is B. Hope this helps! :)