This is true do to all the other particules around
There are 2 moles of NA2SO4 present in 284.078 grams of NA2SO4. Why? Well, we already know here that there are 284.078 grams of NA2SO4. To find how many moles are present in this compound, we would have to divide these grams by the molar mass of the compound. When we go to the periodic table of elements, we will find that there are two moles sodium (which represents 45.98 grams), one mole sulfur (which represents 32.06 grams), and four moles oxygen (which represents 64 grams). When combining these, we would get one mole of sodium sulfate which is representative of 142.04 grams total. That is our molar mass. Now that we have the molar mass, we can go back and divide. 284.078 divided by 142.04 is equal to about 1.99999, and that rounds up to 2 moles. Hence, there are 2 moles of NA2SO4 present in 284.078 grams of NA2SO4.
Your final answer: A is your answer.
answer:
not positive if this is correct just what i ould find on google
Answer:
49.14 carat.
Explanation:
From the question given above, we obtained the following data:
Volume of diamond = 2.8 mL
Mass of diamond (in carat) =.?
Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:
Volume of diamond = 2.8 mL
Density of diamond = 3.51 g/mL
Mass of diamond ( in grams) =?
Density = mass /volume
3.51 = mass /2.8
Cross multiply
Mass of diamond (in g) = 3.51 × 2.8
Mass of diamond (in g) = 9.828 g
Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:
1 g = 5 carat
Therefore,
9.828 g = 9.828 g /1 g × 5 carat
9.828 g = 49.14 carat.
Therefore, the mass of the diamond in carat is 49.14 carat.
