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Scilla [17]
3 years ago
13

How many moles of NH3 can be produced from 3.5 moles of N2

Chemistry
1 answer:
Rufina [12.5K]3 years ago
3 0
1(N2) + 3(H2) --> 2(NH3)
The number in front of the molecules are the mole number

3.5*1(N2) + 3.5*3(H2) --> 3.5*2(NH3)

3.5(N2) + 10.5(H2) --> 7(NH3)

It would produce 7 miles of NH3

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2Na3N3 -&gt; 2Na + 3N2<br><br> if 0.58 mol if NaN3 reacts, what mass of nitrogen would result
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Answer:

                      Mass = 24.36 g of N₂

Explanation:

                   The balance chemical equation for the decomposition of NaNO₃ is as follow;

                                           2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

                 2 moles of NaNO₃ produces  =  3 moles of N₂

So,

              0.58 moles of NaNO₃ will produce  =  X moles of N₂

Solving for X,

                      X = 3 mol × 0.58 mol / 2 mol

                      X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

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