Answer:
the conversion factor is f= 6 mol of glucose/ mol of CO2
Explanation:
First we need to balance the equation:
C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)
the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:
f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction
f = 6 moles of CO2 / 1 mol of glucose = 6 mol of glucose/ mol of CO2
f = 6 mol of CO2/ mol of glucose
for example, for 2 moles of glucose the number of moles of CO2 produced are
n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2
Answer:
2.29 g of N2
Explanation:
We have to start with the <u>chemical reaction</u>:
The next step is to <u>balance the reaction</u>:
We can continue with the <u>mol calculation</u> using the molar mass of
(65 g/mol), so:
Now, with the<u> molar ratio</u> between and 
we can <u>calculate the moles</u> of (2:3), so:
With the molar mass of we can <u>calculate the grams</u>:
I hope it helps!
Answer:The outer core of the Earth contains a lot of iron in a molten state. As the Earth spins this molten iron moves and creates the Earth's magnetic field. The Earth behaves as if there is a huge bar magnet at its centre. The shape of the field around the Earth is very similar to the field around a bar magnet
Explanation:
Answer:
1.7 bar
Explanation:
We can use the <em>Ideal Gas Law</em> to calculate the individual gas pressure.
pV = nRT Divide both sides by V
p = (nRT)/V
Data: n = 1.7 × 10⁶ mol
R = 0.083 14 bar·L·K⁻¹mol⁻¹
T = 22 °C
V = 2.5 × 10⁷ L
Calculations:
(a) <em>Change the temperature to kelvins
</em>
T = (22 + 273.15) K
= 295.15 K
(b) Calculate the pressure
p = (1.7 × 10⁶ × 0.083 14 × 295.15)/(2.5× 10⁷)
= 1.7 bar
