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2 years ago

9

A student tests the properties of an element and finds that it is malleable, shiny, and conducts electricity. Based only on the

student's data, this element is most likely a - .

1 answer:

zysi [14]2 years ago

8 0

Answer:

The most common answer to this would be "Metal".

Explanation:

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The smallest unit of a compound is called a ___________.

Oxana [17]

<span>The smallest unit of a compound is called a molecule. The correct option among all the options that are given in the question is the second option or the penultimate option or option "B". The other choices are incorrrect and can be negated. I hope that this is the answer that has actually come to your desired help.</span>

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2 years ago

If the mass of a liquid reactant is 10g and the mass of a powder reactant is 5g then what should the mass of the product be acco

guapka [62]

Answer:15g

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

10g + 5g ➡️ 15g

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2 years ago

What is 2.15•(6.022•10^23)

sp2606 [1]

Answer:

The answer is 1.29473 x 10^24

Explanation:

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2 years ago

Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen

Darya [45]

Answer: The empirical formula of the compound becomes $CH_2O$

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol$

$\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol$

$\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

$\text{Mole fraction of C}=\frac{3.023}{3.023}=1$

$\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2$

$\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes $CH_2O$

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2 years ago

For the reaction 2 nh3 + ch3oh → products, how much ch3oh is needed to react with 93.5 g of nh3? 1. 1.31 mol 2. 46.8 mol 3. 2.75

DENIUS [597]

3.2.75 mol is the answer.

6 0

3 years ago

Read 2 more answers