2. Malcolm and his bandmate have different ideas for figuring out the equation. Which one do you think will make it easiest to s
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<em>So</em><em> </em><em>the</em><em> </em><em>r</em><em>ight</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>9</em><em>.</em>
<em>Loo</em><em>k</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
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The area of a trapezoid is as follows:
A =
A and B are the lengths of the parallel lines of trapezoids. The parallel lines in this problem are 3.5 and 9.2. After adding those and dividing by 2, we multiply 17 to find the area of the trapezoid. (This is also shown in the attached picture)
The area of a trapezoid is as follows:
A =
A and B are the lengths of the parallel lines of trapezoids. The parallel lines in this problem are 3.5 and 9.2. After adding those and dividing by 2, we multiply 17 to find the area of the trapezoid. (This is also shown in the attached picture)